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Gnesinka [82]
3 years ago
7

Someone help me out I have 30 minutes left on the test

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0
The answer is C because the two lowest lengths of the sides combined must be more than the highest
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Can someone please help me???
olganol [36]

Answer:

1. 60000.12

2. 54000.15

3. 9600.48

4. 3840.48

Step-by-step explanation:

I really hope this helps and may I receive brainliest please

7 0
3 years ago
3-3x6+2 and how is that reached, please!
Dvinal [7]
The order of mathematical operation is MDAS.
M - multiplication
D - division
A - addition
S - subtraction

3 - 3 x 6 + 2

Multiplication : 3 x 6 = 18
Division: none
Addition : + 3 + 2 = 5 (combine positive numbers)
Subtraction : 5 - 18 = -13

3 - 18 + 2 = -13
3 0
3 years ago
60 POINTS PLEASEEEEEEEEEEE
leonid [27]

Answer:

It is B. (0,1)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Urgent help needed...............
andreyandreev [35.5K]

Answer:

Option b is correct

\{x | x \neq \pm 7, x\neq 0\}.

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

h(x) = \frac{9x}{x(x^2-49)}

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

x(x^2-49) = 0

By zero product property;

x = 0 and x^2-49= 0

⇒x = 0 and  x^2 =49

⇒x = 0 and x = \pm 7

Therefore, the domain of the given function is:

\{x | x \neq \pm 7, x\neq 0\}

7 0
3 years ago
Read 2 more answers
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
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