Answer:
2.25 + 1 1/3=3.5833333 combined number of pounds of mulch and gravel sold.
2.25/3.583333 X 172=108 pounds of mulch that the supplier sells
(1 1/3) / 3.583333 X 172=64 pounds of gravel that the supplier sells.
Step-by-step explanation:
Let 'x' = pounds of gravel The ratio of mulch to gravel is given 2 1/4 / 1 1/3 Which equals 9/4 / 4/3 = 27/16
So the total gravel and much is equal to x + 27/16x = 172
Solving for 'x'
43/16 x = 172
x = 172 (16/43) = 64 pounds of gravel Mulch = 27/16x = 64 (27/16)= 108 pounds
Answer:
y = 3
Step-by-step explanation:
The equation of a horizontal line parallel to the x- axis is
y = c
where c is the value of the y- coordinates the line passes through.
here the line passes through (0, 3) with y- coordinate 3
y = 3 ← is the equation of the horizontal line
Step-by-step explanation:

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
I am joyous to assist you anytime.
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