Answer: the balance after 9 years is
$235.8
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $100
r = 10% = 10/100 = 0.1
n = 1 because it was compounded once in a year.
t = 9 years
Therefore,.
A = 100(1 + 0.1/1)^1 × 9
A = 100(1 + 0.1)^9
A = 100(1.1)^9
A = $235.8
Answer:
4
Step-by-step explanation:
Two ways to solve this - either divide 140 by 35 (140/35 = 4)
or keep adding 35 until you reach 140: 35+35+35+35 = 140
| x - 2 | + 4 < 7
-7< x - 2 + 4 < 7
-7 < x + 2 < 7
-9 < x < 5
Answer:
- x = arcsin(√20.5 -3√2) +2kπ . . . k any integer
- x = π - arcsin(√20.5 -3√2) +2kπ . . . k any integer
Step-by-step explanation:
Add √(82) -3sin(x) to both sides to get ...
2sin(x) = √82 -√72
Now, divide by 2 and find the arcsine:
sin(x) = (√82 -√72)/2
x = arcsin((√82 -√72)/2)
Of course, the supplement of this angle is also a solution, along with all the aliases of these angles.
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In degrees, the solutions are approximately 16.562° and 163.438° and integer multiples of 360° added to these.
