H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) 9.8 s

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3 years ago

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A cafeteria worker is wondering how student lunch prices at a high school have changed over time. she researches lunch prices fo

frez [133]

Answer:

Step-by-step explanation:

JAJAJAJAJJAJAJAJQHAJAJJQAJ

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3 years ago

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I Need HELP! how do you figure out 22/7=5/X

Oksana_A [137]

$\frac{22 }{7}= \frac{5}{x} \\ \\ x\neq 0 \\ \\ 22x=7*5\\ \\22x=35 \ \ /:22 \\ \\x=\frac{35}{22}\\ \\x=1\frac{23}{25}$

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3 years ago

5 metric tons = ____ kilograms

ANEK [815]

Answer:

5000

Step-by-step explanation:

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