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3 years ago

Add (-2x + 4) + (4x + 6)

Mathematics

1 answer:

Lostsunrise [7]3 years ago

3 0

Answer:

2x+10

Step-by-step explanation:

Take away parentheses

-2x+4+4x+6

combine -2x+4x and 4+6

2x+10

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If f(x) = x/2 -2 and g(x) = 2x^2 + x - 3, find (f+g) (x) A. 2x^2+3/2x +1 B. 2x^2+3/2x-5 C. x^2 - 6 D. 2X^2- x/2 + 1

Fed [463]

Answer:

$\bold{(f+g)(x)=2x^2+\frac32x-5}$

Step-by-step explanation:

$f(x) =\frac x2-2\quad and\quad g(x) = 2x^2 + x - 3\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=\frac12x-2+2x^2+x-3\\\\(f+g)(x)=2x^2+\frac32x-5$

5 0

3 years ago

I need help with this promblem it’s ALGEBRA 2!

AlekseyPX

Answer:

$(f\circ h)(2)=2$

Step-by-step explanation:

<u>Composite Function </u>

Given f(x) and h(x) real functions, the composite function named $(f\circ h)(x)$ is defined as:

$(f\circ h)(x)=f(h(x))$

It can be found by substituting h into f.

We are given the functions:

$f(x)=2x^2-9x+2$

$h(x)=x^2-4$

It's required to find $(f\circ h)(2)$

As defined above:

$(f\circ h)(x)=f(h(x))$

Thus:

$(f\circ h)(2)=f(h(2))$

Find h(2):

$h(2)=2^2-4=0$

h(2)=0

Now:

$(f\circ h)(2)=2(0)^2-9(0)+2$

$(f\circ h)(2)=2$

8 0

2 years ago

The graph of which function has a minimum located at (4, –3)?

valentinak56 [21]

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

case A) we have

$f(x)=x^{2}+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

$f(x)=-2x^{2}+16x-35$

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point $(4,-3)$ <u>but is not a minimum</u>

see the attached figure

therefore

case B is not the solution

case C) we have

$f(x)=x^{2}-4x+5$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^{2}-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^{2}-4x+4)$

$f(x)-1=(x^{2}-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^{2}$

$f(x)=(x-2)^{2}+1$ --------> vertex form

The vertex is the point $(2,1)$

therefore

case C is not the solution

case D) we have

$f(x)=2x^{2}-16x+35$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-35=2x^{2}-16x$

Factor the leading coefficient

$f(x)-35=2(x^{2}-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^{2}-8x+16)$

$f(x)-3=2(x^{2}-8x+16)$

Rewrite as perfect squares

$f(x)-3=2(x-4)^{2}$

$f(x)=2(x-4)^{2}+3$ --------> vertex form

The vertex is the point $(4,3)$

therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^{2}-16x+29$

7 0

3 years ago

Read 2 more answers

Amy has 2 rows of 4 sports trophies on each of her 3 shelves. how many trophies does she have in all?

sleet_krkn [62]

Each shelf holds 8 trophies (2X4=8). 3 shelves times 8 trophies will equal a total of 24 trophies.

7 0

3 years ago

The sequence that begins with 3, where each succeeding term is twice the preceding term

Fantom [35]

What do we have to find??

4 0

3 years ago