Answer: 0.6065
Step-by-step explanation:
Given : The machine's output is normally distributed with


Let x be the random variable that represents the output of machine .
z-score : 
For x= 21 ounces

For x= 28 ounces

Using the standard normal distribution table , we have
The p-value : 

Hence, the probability of filling a cup between 21 and 28 ounces= 0.6065
<h2>
Answer: -30y + 12u + 18 </h2>
<h3>
Step-by-step explanation:</h3>
<em> by multiplying each term in the parentheses by the term outside</em>
-6(5y-2u-3) = (-6 × 5y) + (-6 × - 2u) + (-6 × -3)
= -30y + 12u + 18
Answer:
y = 5x – 22
3x + 2y = 34
Step-by-step explanation: