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2 years ago

Is the point (1,2) on the graph of f(x)=3x-1 (Show full working)

Mathematics

1 answer:

Maslowich2 years ago

3 0

Answer:

$f(x) = 3x - 1 \\2 = 3(1) - 1 \\ 2 = 2 \\ \therefore \: the \: point \: \binom{1}{2} \: is \: on \: the \\ graph \: of \: f(x) = 3x - 1$

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Shaun had a collection of 840 matchbox vehicles. Of these vehicles, 15% are four-wheelers and 30% are convertibles. The rest are

lakkis [162]

Answer:

Step-by-step explanation:

15% of 840 is 126

30% of 840 is 252

252

+ 126

378

840 - 378 = 462

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55% of 840 is...

462

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Hope this helps! <3

5 0

3 years ago

Read 2 more answers

15. A restaurant has one type of milk that has 2% fat and another that has 7% fat. how many quarts of each type does the restaur

krek1111 [17]

B. 16 quarts of the 2% milk and 24 quarts of the 7% milk First, let's create an equation to solve. x = quarts of 2% milk (40-x) = quarts of 7% milk So we have the equation x*2 + (40-x)*7 = 40*5 Now to solve for x x*2 + (40-x)*7 = 40*5 x*2 + 7*40 - 7*x = 40*5 x*2 - 7*x = 40*5 - 7*40 -5*x = - 2*40 x = 2*8 x = 16 So we need 16 quarts of 2% milk and 40-16 = 24 quarts of 7%, which matches option "B".

5 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$