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3 years ago

Could someone please help me solve this? Thanks!!

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

7 0

I'm honestly not too sure, good luck on people to answer you!

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5r^2-13r-6=0 How do I solve this

frosja888 [35]

$5 {r}^{2} - 13r - 6 = 0 \\ a = 5 \\ b = - 13 \\ c = - 16 \\$

r= -(-13)±>

$\sqrt{( - 13) {}^{2} } - 4.5( - 6)$

2.5

r= 13±17

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r=13+17

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r=13-17

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$r = 2 \\ r = \frac{ - 2}{5}$

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3 years ago

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2 years ago

The positive integer k has exactly two positive prime factors, 3 and 7. if k has a total of 6 positive factors, including 1 and

Sav [38]

I think there are two solutions, 63 or 147:

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What is the value of 3.5 (11) + 1.9 (11) + 1.6 (11)?

Goryan [66]

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