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wel
3 years ago
7

Un Emperador Griego Nació En el Año 48 A.C Y Murió En El 10 D.C ¿Cuántos Años Vivió?

Mathematics
2 answers:
ankoles [38]3 years ago
7 0
58 porque antes de c los numeros iban hacia atras y despues de c van normal como ahora

velikii [3]3 years ago
4 0
13 - <span>Augusto </span>emperador<span> romano </span>nacio<span> en el </span>año<span> 63 </span>a.c<span> y </span>murio<span> en el 14 ... considera que desde el </span>año<span> 63 </span>ac<span> hasta el </span>año<span> 0 hay 63 </span>años<span> y del </span>año<span> 0 ... El 80% de las preguntas recibe respuesta en menos de </span>10<span> minutos ... Un terreno tiene de area 12x3 4x2 si uno de sus lados mide 2x ¿</span>cuanto<span> mide el lado Q ?

</span>
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Please i really need help!!! thnakss
Naddik [55]

Answer:

The first answer will be 96 batches and the second one will be 0.90 cents per batch

Step-by-step explanation:

Hope this Helped

5 0
3 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
Please help.. thanks if you do :)
AlladinOne [14]

Answer:

it  X+3

it 3 hope this help yuuu

Step-by-step explanation: 6(x+2)=30

6x+6.2=5

6(x+2)=30

6x + 12 = 30

     -12    -12

6x = 18

x = 3

hope this help the best answer is X=3

tht the bnest answer for the q

6 0
3 years ago
Read 2 more answers
What is an estimate for 17 divided by 1569
Y_Kistochka [10]
It will be 93 because it 92 but you have to round up with deimal number
5 0
3 years ago
Read 2 more answers
A submarine starts at 0 units and has groups of 3 floats and groups of 4 anchors attached.
Novosadov [1.4K]

Answer:

isn't -8, right?

Step-by-step explanation:

im not really good at math.

3 0
3 years ago
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