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Gennadij [26K]
3 years ago
14

Choose the equation that represents a line that passes through points (−3, 2) and (2,1).

Mathematics
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Slope: (2-1)/(-3-2) = -⅕

y = (-⅕)x + c

1 = (-⅕)(2) + c

c = 7/5

y = (-1/5)(x) + (7/5)

5y = -x + 7

x + 5y = 7

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Katie is To Receive 2-1/2 drops of medication every 6hours. How much Medication will she receive in 24 hours?
bezimeni [28]
First, how many periods of 6 hours are in 24 hours? 24 / 6 = 4.
So every 6 hours, Katie needs 2.5 drops.
Seeing as there are 4 periods of 6 hours in 24 hours, you would do 2.5 x 4.
Katie will receive 10 drops of medication in 24 hours. 
6 0
3 years ago
Brainiest to whoever right
Anna35 [415]

Answer:

since M lies between point A and B , we came to know that,

M(4,6) =(x,y)

A(-2,-1)=(x1 ,y1)

B( _, _ )=(x2,y2)

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x=x1×x2÷2 y=y1+y2÷2

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6 0
3 years ago
What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 can
Wewaii [24]

Answer:

Hello your question is incomplete below  is the complete question

What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =

answer : The value of f(7) = 29

Step-by-step explanation:

Attached below is the detailed solution

Hence : F(7) - 14 = 15

F(7) = 15 + 14 = 29

8 0
4 years ago
Simplify 81 to the negative 3 fourths power.
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3 0
4 years ago
PLEASE ANSWER ASAP! *picture attached* :)
ser-zykov [4K]

Answer:

3ab^2+a^2-b^2-ab

6 0
3 years ago
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