All categories

3 years ago

Rewrite the equation by completing the square. x^2 - 4x + 3 = 0

Mathematics

2 answers:

maw [93]3 years ago

8 0

Answer:

After completing the square, we can say:

(x - 2)² = 1

If we solve for x, this tells us that x has a value of both 1 and 3.

Step-by-step explanation:

Given:

x² - 4x + 3 = 0

We can complete the square by adding 1 to both sides:

x² - 4x + 4 = 1

(x - 2)² = 1

We can then solve for x by saying:

(x - 2)² = 1

x - 2 = √1

x = 2 ± 1

x = 1, 3

Degger [83]3 years ago

4 0

Answer:

the answer would be x=3,1

You might be interested in

Simplify. 16 - 8 + 5x - 3x 16 + 2x 8 + 8x 8 + 2x 10x

klio [65]

Answer:

8+2x

Step-by-step explanation:

Combine Like Terms:

16-8+5x-3x

8+5x-3x

8+2x

3 0

3 years ago

Read 2 more answers

Can someone help out with #3? I'll give Brainliest answer.

quester [9]

The answer is 4√6 4√x
Sorry if that looks confusing but it means small 4, big 6 and then small 4

7 0

4 years ago

What are the rules when multiplying/dividing fractions?

Mashutka [201]

Answer:

To multiply fractions, all you have to do is multiply the numerators and denominators and simplify the result. To divide fractions, you simply have to flip the numerator and denominator of one of the fractions, multiply the result by the other fraction, and simplify.

Step-by-step explanation:

hope this helps

plz mark brainliest

8 0

3 years ago

Read 2 more answers

(HELP ME 15 PTS)

kap26 [50]

Answer: $\bold{\dfrac{27x^2y^3}{16}}$

Step-by-step explanation:

$\dfrac{(3x^2y^5)^3}{(2xy^3)^4}\\\\\\=\dfrac{3^3\cdot x^{2\cdot 3}\cdot y^{5\cdot 3}}{2^4\cdot x^4\cdot y^{3\cdot 4}}\\\\\\=\dfrac{27\cdot x^6\cdot y^{15}}{16\cdot x^4\cdot y^{12}}\\\\\\=\dfrac{27\cdot x^{6-4}\cdot y^{15-12}}{16}\\\\\\=\dfrac{27\cdot x^2\cdot y^3}{16}$

8 0

3 years ago

The garden club

dedylja [7]

Answer:

here's a link

bit. ly/3gVQkw3

3 0

3 years ago