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ValentinkaMS [17]
4 years ago
5

Which statement describes a convex lens?

Mathematics
2 answers:
SpyIntel [72]4 years ago
8 0

) It bends light rays inward.

marusya05 [52]4 years ago
3 0

Answer:

B) It bends light rays inward.

Step-by-step explanation:

Convex lens are also known as converging lens since they bend the light inwards so that they converge together. Convex lens are always thickest at the middle and thin at the upper and lower edges. They are generally made of plastic or glass. They do not absorb most light, they magnify the image, e.g. magnifying glasses use convex lens.

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Samantha wants to use her savings of 1150 to buy shirts and watches for her family. The total price of the shirt she bought was
ioda

<u>Answer-</u>

<em>The maximum number of watches that Samantha come by with her savings is </em><em>10</em><em>.</em>

<u>Solution-</u>

The amount of money Samantha has in her savings account = $1150

She wants to buy shirts and watches.

Cost of one shirt = $84

Cost of each watch = $99

Let she can buy maximum of x watches, so the net price of the watches is $99x.

Then,

\Rightarrow 99x+84=1150\\\\\Rightarrow 99x=1150-84\\\\\Rightarrow 99x=1066\\\\\Rightarrow x=\dfrac{1066}{99}\\\\\Rightarrow x=10.77

As the number of watches can not be in fraction, so at most she can buy 10 watches.

8 0
3 years ago
Is 21,063 divisible by three? If it is, write a number as a product of three and another factor if not, explain
Zarrin [17]
Twenty-one thousand and sixty-three divided by three is 7021

First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
4 0
3 years ago
Find the value of x. Round the length to the nearest tenth.
attashe74 [19]

I donno is there anything else

8 0
3 years ago
Find the annual rate of interest. Principal = 4600 rupees Period = 5 years Total amount = 6440 rupees Annual rate of interest =
Semmy [17]

Answer:

The rate of interest for compounded annually is 6.96 %  .

Step-by-step explanation:

Given as :

The principal amount = Rs 4600

The time period = 5 years

The amount after 5 years = Rs 6440

Let The rate of interest = R %

<u>From compounded method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm Time}

or, Rs 6440 = Rs 4600 × (1+\dfrac{\textrm R}{100})^{\textrm 5}

Or, \frac{6440}{4600} =  (1+\dfrac{\textrm R}{100})^{\textrm 5}

or, 1.4 =  (1+\dfrac{\textrm R}{100})^{\textrm 5}

Or, (1.4)^{\frac{1}{5}} = 1 + \dfrac{R}{100}

or, 1.0696 =  1 + \dfrac{R}{100}

or, \dfrac{R}{100} = 1.0696 - 1

Or, \dfrac{R}{100} = 0.0696

∴ R = 0.0696 × 100

I.e R = 6.96

Hence The rate of interest for compounded annually is 6.96 %  .  Answer

5 0
3 years ago
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
4 years ago
Read 2 more answers
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