<u>Answer-</u>
<em>The maximum number of watches that Samantha come by with her savings is </em><em>10</em><em>.</em>
<u>Solution-</u>
The amount of money Samantha has in her savings account = $1150
She wants to buy shirts and watches.
Cost of one shirt = $84
Cost of each watch = $99
Let she can buy maximum of x watches, so the net price of the watches is $99x.
Then,

As the number of watches can not be in fraction, so at most she can buy 10 watches.
Twenty-one thousand and sixty-three divided by three is 7021
First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
I donno is there anything else
Answer:
The rate of interest for compounded annually is 6.96 % .
Step-by-step explanation:
Given as :
The principal amount = Rs 4600
The time period = 5 years
The amount after 5 years = Rs 6440
Let The rate of interest = R %
<u>From compounded method</u>
Amount = Principal × 
or, Rs 6440 = Rs 4600 × 
Or,
= 
or, 1.4 = 
Or,
= 1 + 
or, 1.0696 = 1 + 
or,
= 1.0696 - 1
Or,
= 0.0696
∴ R = 0.0696 × 100
I.e R = 6.96
Hence The rate of interest for compounded annually is 6.96 % . Answer
Answer:
Second choice:


Fifth choice:


Step-by-step explanation:
Let's look at choice 1.


I'm going to subtract 1 on both sides for the first equation giving me
. I will replace the
in the second equation with this substitution from equation 1.

Expand using the distributive property and the identity
:




So this not the desired result.
Let's look at choice 2.


Solve the first equation for
by dividing both sides by 2:
.
Let's plug this into equation 2:



This is the desired result.
Choice 3:


Solve the first equation for
by adding 3 on both sides:
.
Plug into second equation:

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:



Not the desired result.
Choice 4:


I'm going to solve the bottom equation for
since I don't want to deal with square roots.
Add 3 on both sides:

Divide both sides by 2:

Plug into equation 1:

This is not the desired result because the
variable will be squared now instead of the
variable.
Choice 5:


Solve the first equation for
by subtracting 1 on both sides:
.
Plug into equation 2:

Distribute and use the binomial square identity used earlier:



.
This is the desired result.