It’s x=0 isn’t it that answer
Answer:
25
Step-by-step explanation:
(50 cm (centimeters))/(20 mm (millimeters))
Result:
25 m/m (meters per meter)
25
2500%
Unit conversions:
15.53 mi/km (miles per kilometer)
25 mi/mi (miles per mile)
25 squares
Interpretation:
length ratio
2 m/s²
Step-by-step explanation:
Step 1:
Let the initial velocity be 0 m/s and the final velocity be 8 m/s and the time traveled is 4 s.
From the basic science,
Acceleration = ( Final Velocity - Initial Velocity) / Time
Step 2:
Acceleration = (8-0)/4
2 m/s²
Answer:
you do rise over run in the case you go up 4 and go across 2
Step-by-step explanation:
There's nothing preventing us from computing one integral at a time:
![\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E%7B2-x%7D%20xyz%20%5C%2C%5Cmathrm%20dz%20%3D%20%5Cfrac12xyz%5E2%5Cbigg%7C_%7Bz%3D0%7D%5E%7Bz%3D2-x%7D%20%5C%5C%5C%5C%20%3D%20%5Cfrac12xy%282-x%29%5E2)
![\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E%7B1-x%7D%5Cint_0%5E%7B2-x%7Dxyz%5C%2C%5Cmathrm%20dz%5C%2C%5Cmathrm%20dy%20%3D%20%5Cfrac12%5Cint_0%5E%7B1-x%7Dxy%282-x%29%5E2%5C%2C%5Cmathrm%20dy%20%5C%5C%5C%5C%20%3D%20%5Cfrac14xy%5E2%282-x%29%5E2%5Cbigg%7C_%7By%3D0%7D%5E%7By%3D1-x%7D%20%5C%5C%5C%5C%3D%20%5Cfrac14x%281-x%29%5E2%282-x%29%5E2)
![\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_0%5E1%5Cint_0%5E%7B1-x%7D%5Cint_0%5E%7B2-x%7Dxyz%5C%2C%5Cmathrm%20dz%5C%2C%5Cmathrm%20dy%5C%2C%5Cmathrm%20dx%20%3D%20%5Cfrac14%5Cint_0%5E1x%281-x%29%5E2%282-x%29%5E2%5C%2C%5Cmathrm%20dx)
Expand the integrand completely:
![x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x](https://tex.z-dn.net/?f=x%281-x%29%5E2%282-x%29%5E2%20%3D%20x%5E5-6x%5E4%2B13x%5E3-12x%5E2%2B4x)
Then
![\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac14%5Cint_0%5E1x%281-x%29%5E2%282-x%29%5E2%5C%2C%5Cmathrm%20dx%20%3D%20%5Cleft%28%5Cfrac16x%5E6-%5Cfrac65x%5E5%2B%5Cfrac%7B13%7D4x%5E4-4x%5E3%2B2x%5E2%5Cright%29%5Cbigg%7C_%7Bx%3D0%7D%5E%7Bx%3D1%7D%20%5C%5C%5C%5C%20%3D%20%5Cboxed%7B%5Cfrac%7B13%7D%7B240%7D%7D)