So i've been having some real trouble understanding Trigonometry-sine ratio, and was wondering if anybody could explain to me ho
w to do it? It would be awesome if you could :< i put a problem below thanks if you do, its greatly appreciated
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Answer:
Step-by-step explanation:
Right triangle trig. Super fun! We are given the vertex angle of 27 degrees. The side across from that angle is 4, and we are looking for the hypotenuse of the triangle. That is the trig ratio sin. sin of an angle is equal to the side opposite over the hypotenuse:
and, solving for hyp:
. Do that on your calculator in degree mode to get that the hypotenuse, side BD is 8.8 units.