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Kaylis [27]
3 years ago
13

What is 5(3x+2)-2(4x-1)

Mathematics
1 answer:
sweet [91]3 years ago
7 0
5(3x+2)-2(4x-1) 

15x+10-8x+2 

(15x-8x)+(10+2) 

7x+12
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On a road trip to visit her grandparents,
gavmur [86]

Answer:

2 hours

Step-by-step explanation:

3 0
2 years ago
PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!
Nookie1986 [14]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2-x-4}

Step-by-step explanation:

The equation of a parabola in vertex form:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

The focus is

\left(h,\ k+\dfrac{1}{4a}\right)

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using k+\dfrac{1}{4a}

<em>k = -5</em>

-5+\dfrac{1}{4a}=-4        <em>add 5 to both sides</em>

\dfrac{1}{4a}=1           <em>multiply both sides by 4</em>

4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4

\dfrac{1}{a}=4\to a=\dfrac{1}{4}

Substitute

a=\dfrac{1}{4},\ h=2,\ k=-5

to the vertex form of an equation of a parabola:

y=\dfrac{1}{4}(x-2)^2-5

The standard form:

y=ax^2+bx+c

Convert using

(a-b)^2=a^2-2ab+b^2

y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5

<em>use the distributive property: a(b+c)=ab+ac</em>

y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4

3 0
3 years ago
Find the nth term of the sequence:<br>23, 19, 13, 5, -5.......<br>​
Maurinko [17]

Answer:

Step-by-step explanation:

Given the sequence :

23, 19, 13, 5, -5.......

From the sequence, the common difference is unequal, as their is a constant Increment in the difference after successive numbers.

19 - 23 = -4

13 - 19 = -6

5 - 13 = -8

-5 - 5= -10

Hence an constant difference of - 2 after each successive difference.

Hence, this is a quadratic sequence

With the formula

an² + bn + c

8 0
3 years ago
Simplify the expression -2(y-1)+3(y+2)
romanna [79]

Answer:  y+8

Step-by-step explanation:

-2(y-1)+3(y+2)

-2y+2+3y+6

y+8

6 0
3 years ago
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Travka [436]
I dont have an answer buy i need to answer a question so i can ask my question sry
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3 years ago
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