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mariarad [96]
3 years ago
5

Where is my phone? I seem to have lost my phone. I know where I last saw it but it has been moved since then and I need help to

locate it. It started at the following coordinates A (14, -12); B (14, -19); C (10, -19); D (10, -14); E (13, -14); F (13, -12). My Mom told me she translated it 6 units to the left Then my little brother said he had reflected it over the Y-axis My friend many found it and translated it 9 units up Dad said he tripped over it and reflected it over the X-axis My sister then rotated it 900 clockwise Uncle Jose translated it 5 units left and 4 units down Cousin Michelle then said she rotated it 900 clockwise Finally my dog picked it up and translated it 5 units down and 10 units to the right Where is my phone? Using the scenario on this page do the following. Graph the preimage using the given points. Label points (A, B, C, ...)​ Transform the objects using the information provided. Show each transformation and label. (A', B', C', ...) Determine the final location. Write a 2 to 3 sentence explain on how you found the phone location.

Mathematics
1 answer:
Maru [420]3 years ago
7 0

Answer:

  see attached

Step-by-step explanation:

The attachments show the initial (brown) and final (blue) positions of the phone. The spreadsheet shows all the intermediate locations and the formulas used to determine them.

The two reflections cancel the total of 180° of CW rotation, so the net result is simply a translation. That translation is up by 9 units.

__

Translation up adds to the y-coefficient; translation right adds to the x-coefficient. Down or left use negative values.

90° CW does this: (x, y) ⇒ (y, -x)

Reflection across y does this: (x, y) ⇒ (-x, y)

Reflection across x does this: (x, y) ⇒ (x, -y)

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25

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200 divided by 8

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Find the arc length with the given information <br> central angle=pi/4 radius=2
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Question 6
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3 years ago
You and your friend are selling tickets to a charity event. You sell 8 adult tickets and 6 student tickets for $126. Your friend
AnnyKZ [126]
S=cost per student ticket
a=cost per adult ticket

value=(students vlue)+(adults value)
student value=(cost per student) times number of students
adult value=(cost per adult) times number of adults



you sell 8 adult and 6 students and that is a value of 126
8a+6s=126

friend sell12 adult and 13 student and get 209
12a+13s=209

so we have
8a+6s=126 and
12a+13s=209
it might help to simplify  the first equaiton by dividing by 2
4a+3s=63

we have
4a+3s=63
12a+13s=209
multiply first equaton by -3
-12a-9s=-189

add to secont equaiton

12a+13s=209
<u>-12a-9s=-189 +
</u>0a+4s=20<u> </u>

4s=20
divide 4
s=5

each student ticket costs $5.00
8 0
3 years ago
I places.<br> 3) Base area<br> =<br> 148 ft?<br> 10 ft<br> Volume =
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Answer:

see explanation.

Step-by-step explanation:

148 ft. = Area.

37 * 4 = 148 sq. ft.

Perimeter = 82 ft.

2(37 + 4) = 82 ft.

hope this helps.

8 0
3 years ago
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