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meriva
3 years ago
9

Lkmkmklmklmkbuyubyubybyubyubybbbhuybyhhyubybhu

Mathematics
2 answers:
VLD [36.1K]3 years ago
6 0

Answer:

woahedofhodfsajgnewjkfan;l

Step-by-step explanation:

Alenkinab [10]3 years ago
6 0

Answer:

bubucuyebcuuygfesghugfy

Step-by-step explanation:

hunurfbeaoiuobef

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The graph below shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet: Pa
Advocard [28]

the complete question in the attached figure

part A

the x intercept 0 is the point where the ball was hit, the x intercept 20 is the point where the ball fell back to the ground, 20 feet away from the kicker.

<span>the function is increasing in the interval x∈(0, 10) and decreasing in x∈(10, 20) </span>
this means that the height is increasing in the interval  (0, 10) and decreasing as x goes through the interval (10,20)
the distance from the kicker is increasing during the whole interval (0, 20)

part B

the rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases or increases in the interval 

x =[A, B]

from x = 22 to x = 26-------------- > the function does not exist


5 0
3 years ago
Evaluate. 12+4⋅3−15 Enter your answer in the box.
Nina [5.8K]

Answer:

the answer is 1.3

Step-by-step explanation:

12+4.3 is 16.3

16.3-15 is 1.3

7 0
3 years ago
Read 2 more answers
-8(2b-7)-9(b-5)<br>simplify ​
GenaCL600 [577]

Answer:

<h2>-25b + 101</h2>

Step-by-step explanation:

-8(2b-7)-9(b-5)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(-8)(2b)+(-8)(-7)+(-9)(b)+(-9)(-5)\\\\=-16b+56-9b+45\qquad\text{combine like terms}\\\\=(-16b-9b)+(56+45)\\\\=-25b+101

3 0
3 years ago
Read 2 more answers
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
BigorU [14]
You have two 30-60-90 triangles, ADC and BDC.

The ratio of the lengths of the sides of a 30-60-90 triangle is

short leg : long leg : hypotenuse
     1        :  sqrt(3)  :        2

Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC

First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30

Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10

AB = AC - BC = 30 - 10 = 20
6 0
3 years ago
Read 2 more answers
Please answer this correctly
Fantom [35]

Answer:

4 weeks 5 days

Step-by-step explanation:

3 0
4 years ago
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