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zhannawk [14.2K]
3 years ago
7

There is a rectangle ABCD, with sides AB = CD = 32, and sides and BC = DA = 24. The rectangle is rotated 90° clockwise about C,

then rotated 90° clockwise about the new location of point that D after the first rotation. What is the length of the path travelled by point A?

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0

Answer

given,

side of rectangle, AB = CD = 32

                              BC = DA = 24

rectangle is rotated 90° clockwise about C.

then rotated 90° clockwise about D.

Path traveled by the point A for first rotation will be in circle with radius AC.

   D_1 = \dfrac{\theta_1}{360^0}\times \pi \times {AC}^2

      AC = \sqrt{24^2+32^2}

             AC = 40

             θ₁ = 90°

   D_1 = \dfrac{90^0}{360^0}\times \pi \times {40}^2

         D₁ = 1256.64

For the second rotation Point A will move in circular path with radius of AD

   D_2 = \dfrac{\theta_2}{360^0}\pi {AD}^2

             AD = 24

             θ₁ = 90°

   D_2 = \dfrac{90^0}{360^0}\times \pi \times {24}^2

         D₂ = 452.39

total path traveled by the point A

   D = D₁ + D₂

   D = 1256.64 + 452.39

  D = 1709.03

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She would have 3.4 chicken nuggets i she spent $5 so she would have 3 chicken nuggets.

Step-by-step explanation:

17.00 divided by 5 = 3.4 or round down to 3.

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6 0
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What is the solution to the system of equations
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Step-by-step explanation:

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8 0
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Solve for x.<br> 4x +4=12
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Answer:

x = 2

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8 0
3 years ago
Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)
USPshnik [31]
See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) +  f(\frac{x_{1} + x_{2} }{2}) + ... +  f(\frac{x_{n-1} + x_{n} }{2})]

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
M_{4} = \frac{1 - 0}{4} [ f(\frac{0 +  \frac{1}{4} }{2}) +  f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) +  f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]
M_{4} = \frac{1}{4} [ f(\frac{1}{8}) +  f(\frac{3}{8}) +  f(\frac{5}{8}) + f(\frac{7}{8})]

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]

M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]

M₄ = 1/4 · (2 - 478/512)
     = 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0
4 years ago
In the accompanying diagram, line n is parallel to
mote1985 [20]
Here too same procedure
4) 156 is the answer
4 0
3 years ago
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