Measure of angle 5 i.e. m∠5 = 50°
<h3>
What is measurement of an angle ?</h3>
The measurement of angle is the degree of that angle or we can also say that the angles are always measured in degree. In geometry, the complete one revolution of four quadrants is of 360 degrees (360°) and divided into total of 360 parts where each part of this represents a degree.
<h3>
How to find angle measurement ?</h3>
As stated above there are total 360 parts in one revolution thus thus we can find value of particular angle by subtracting the angle from 360 or 180 for a straight line.
In the question,
Let given angle is ∠8.
Given, ∠8 = 50°
Now, according to vertical angle property
∠5 = ∠8
therefore, ∠5 = 50°
Thus, m∠5 = 50°
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The complete question is :
Find measure m∠5
Answer:
Part A: Carie is not correct
Part B: D(2 ,1)
Step-by-step explanation:
I need more details
Answer:
Rectangle D is reflected over the x-axis and then translated 8 units right will result in rectangle E
Step-by-step explanation:
The coordinates of rectangle D are:
(-1, 1)
(-1, 4)
(-3, 1) and
(-3, 4)
The rule of reflection across x-axis is given by:
Next, translate this 8 unit right which is given by:
⇒(7, -1) , (5, -1) , (5, -4) and (7, -4) represents the coordinate of rectangle E.
Therefore, Rectangle D if reflected over the x-axis and then translated 8 units right will result in rectangle E
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
show the picture
Step-by-step explanation:
