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monitta
3 years ago
14

Wonderful people, please come in and try to help me. Please, only real comments not a random answer.

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0

Answer:

C.

Step-by-step explanation:

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Simply the problem.
Marat540 [252]

Answer:

C

Step-by-step explanation:

\sqrt{3}\cdot\sqrt{21}= \\\\\sqrt{3\cdot 21}= \\\\\sqrt{63}= \\\\3\sqrt{7}

Therefore, the correct answer is choice C. Hope this helps!

6 0
3 years ago
Read 2 more answers
I'm solving systems and I don't understand how to do it pls helpp
kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0
2 years ago
Read 2 more answers
4x+11<23 solve for x
jarptica [38.1K]
Let's solve your inequality step-by-step.
<span><span><span>4x</span>+11</span><23
</span>Step 1: Subtract 11 from both sides.
<span><span><span><span>4x</span>+11</span>−11</span><<span>23−11</span></span><span><span>4x</span><12
</span>Step 2: Divide both sides by 4.<span><span><span>4x</span>4</span><<span>124</span></span><span>x<3
</span><u>Answer:
</u><span>   x<<span>3</span></span>
8 0
3 years ago
Look at picture. Does anybody know the answer I’m lost?
masha68 [24]

Let x,y be the dimensions of the rectangle. We know the equations for both area and perimeter:

A=xy=36

P=2(x+y)=36 \iff x+y=18

So, we have  the following system:

\begin{cases}xy=36\\x+y=18\end{cases}

From the second equation, we can deduce

y=18-x

Plug this in the first equation to get

xy=x(18-x)=-x^2+18=36

Refactor as

x^2-18x+36=0

And solve with the usual quadratic formula to get

x=9\pm3\sqrt{5}

Both solutions are feasible, because they're both positive.

If we chose the positive solution, we have

x=9+3\sqrt{5} \implies y=18-x=18-9-3\sqrt{5}=9-3\sqrt{5}

If we choose the negative solution, we have

x=9-3\sqrt{5} \implies y=18-x=18-9+3\sqrt{5}=9+3\sqrt{5}

So, we're just swapping the role of x and y. The two dimensions of the rectangle are 9+3\sqrt{5} and 9-3\sqrt{5}

6 0
2 years ago
Which number is a factor of 13?
ioda
13 is a prime number so its only factors are 1 and 13
7 0
3 years ago
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