Answer:
see explanation
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ), thus
H(5, 0 ) → H'(- 5, 0 )
I(- 6, - 3 ) → I'(6, - 3 )
(x + y)^5 = 1·x^5·y^0 + 5·x^4·y^1 + 10·x^3·y^2 + 10·x^2·y^3 + 5·x^1·y^4 + 1·x^0·y^5
Correct is only A
picture is attached
there are many options but this is one
Answer:D
Did it on khan academy