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Stella [2.4K]
3 years ago
14

The length of a rectangle is 4 units shorter than half the width. If the length of the rectangle is 18 units, which equation can

be used to find w, the width of the rectangle?
Mathematics
2 answers:
ollegr [7]3 years ago
8 0
The answer is a  18= w/2-4
maria [59]3 years ago
4 0
Using x for width (x/2)-4=18. completely solved x=44
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in my fish tank the ratio of the redfish to bluefish is 3:5 there are 20 bluefish how many red fish are there
qwelly [4]
Let x be the number of red fish
3:5 = x:20
3/5 = x/20
(Cross method)
5x = 60
x =12

There are 12 red fish in the fish tank.
7 0
3 years ago
Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0
3 years ago
Translate into a variable expression.<br> fifteen more than one-half of the square of z
stellarik [79]

Answer:

15 +(1/2)X z²

this is your expression plz brainlist me and follow me

5 0
3 years ago
Mr. James stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the groun
kozerog [31]

Answer:

42 m above the ground

Step-by-step explanation:

4 0
3 years ago
50 points! Tell whether the orthocenter is inside, on, or outside the triangle. Then find the coordinates of the orthocenter.
Nady [450]

Answer:

  • (1,3) is inside the triangle

Step-by-step explanation:

Orthocenter is the intersection of altitudes.

We'll calculate the slopes of the two sides and their altitudes ad find the intersection.

<h3>Side QR</h3>
  • m = (3 - 5)/(4 - (-1)) = -2/5

<u>Perpendicular slope:</u>

  • -1/m = 5/2

<u>Perpendicular line passes through S(-1, -2):</u>

  • y - (-2) = 5/2(x - (-1)) ⇒ y = 5/2x + 1/2
<h3>Side RS</h3>
  • m = (-2 - 3)/(-1 -4) = -5/-5 = 1

<u>Perpendicular slope:</u>

  • -1/m = -1/1 = -1

<u>Perpendicular line passes through Q(-1, 5):</u>

  • y - 5 = -(x - (-1)) ⇒ y = -x + 4

The intersection of the two lines is the orthocenter.

<u>Solve the system of equations to get the coordinates of the orthocenter:</u>

  • 5/2x + 1/2 = x + 4
  • 5x + 1 = -2x + 8
  • 7x = 7
  • x = 1

<u>Find y-coordinate:</u>

  • y = -1 + 4 = 3

The orthocenter is (1, 3)

If we plot the points, we'll see it is inside the triangle

6 0
3 years ago
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