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yulyashka [42]
3 years ago
10

Math WHAT is the least common multiple of 12 and 18

Mathematics
2 answers:
mr Goodwill [35]3 years ago
3 0

The least common multiple of 12 and 18 should be 2

sammy [17]3 years ago
3 0

The least common multiple of 12 and 8 is 2

2, 4, 6, 8, 10, 12, 14, 16...


Hope this helps

-AaronWiseIsBae

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Which of the following is equivalent to the expression below sqrt 8 - sqrt 72 + sqrt 50
mash [69]

Answer:

Step-by-step explanation:

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Simplify by taking the prime factorization of each of those numbers.

8: 4*2 and 4 is a perfect square, so we'll stop there

72: 36*2 and 36 is a perfect square, so we'll stop there

50: 25*2 and 25 is a perfect square, so we'll stop there.

Now, rewrite each one of them in terms of their prime factorization:

\sqrt{4*2}-\sqrt{36*2}+\sqrt{25*2} and then pull out each perfect square as its root:

2\sqrt{2}-6\sqrt{2}+5\sqrt{2} and now all the radicands are the same, so we can add them to get

1\sqrt{2}  or simply  \sqrt{2}

6 0
2 years ago
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Solve the following system of equations for all three variables.
nignag [31]
  5x - 2y + 1z = 8 ⇒   5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
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 5x -  2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
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    -18x - 3z =   9
           -22x = 22
            -22    -22
                x = -1
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-18(-1) - 3z = 9
       18 - 3z = 9
     - 18       - 18
             -3z = -9
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stellarik [79]

ANSWER

{x | x \in \: R}

EXPLANATION

From the graph, the given quadratic inequality is

{(x + 3)}^{2}  \geqslant 0

We can see that the corresponding quadratic function is a perfect square.

Since the graph opens upwards and it is always above the x-axis, any real number you plug into the inequality, the result is greater than or equal to zero.

Hence the solution set is

{x | x \in \: R}

The correct answer is A

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navik [9.2K]

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Answer:

  see below

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Multiply the numbers as though they were integers, then mark off a number of decimal places in the product equal to the total number of decimal places in the numbers being multiplied (1).

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