Question

What is an equation of the line that passes through (-2,3) and (6,-1)?

Answer 1

Answer:

Step-by-step explanation:

Slope = (-1-3)/(6+2) = -4/8 = -1/2

Equation of a line is

y-y1 = m(x-x1)

y-3 = (-1/2)(x+2)

y = 3 + (-1/2)(x+2)