Answer:
v-2u=10j
Step-by-step explanation:
The component of vector v, are
u=<6,-4>
From the graph; vector u, has components.
v=<12,2>
We perform the subtraction;
v-2u=<12,2>-2<6,-4>
We multiply out the scalar to get:
v-2u=<12,2>-<12,-8>
This implies that;
v-2u=<12-12,2--8>
v-2u=<0,10>
v-2u=0i+10j
0i + 10j, or just 10j
Vector u = <6, -4> and vector v = <12, 2>.
We are to find v - 2u, which is:
<12, 2> - 2<6, -4>. We combine x components and y components to obtain:
<12-12, 2+8>, or <0, 10>.
In terms of i and j, that'd be 0i + 10j, or just 10j.
I think the answer is BD ≅ CE
2 units
It's because the only whole number factor pair to 10 is 2x5 and luckily, it turned out that 5-3=2, so there are no decimals or fractions.