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777dan777 [17]
3 years ago
11

given vector u = (6,-4) and the graph of vector v, find v - 2u and express the result of terms in i and j

Mathematics
2 answers:
Valentin [98]3 years ago
8 0

Answer:

v-2u=10j

Step-by-step explanation:

The component of vector v, are

u=<6,-4>

From the graph; vector u, has components.

v=<12,2>

We perform the subtraction;

v-2u=<12,2>-2<6,-4>

We multiply out the scalar to get:

v-2u=<12,2>-<12,-8>

This implies that;

v-2u=<12-12,2--8>

v-2u=<0,10>

v-2u=0i+10j

v-2u=10j

Andre45 [30]3 years ago
4 0

Answer:

0i + 10j, or just 10j

Step-by-step explanation:

Vector u = <6, -4> and vector v = <12, 2>.

We are to find v - 2u, which is:

<12, 2> - 2<6, -4>.  We combine x components and y components to obtain:

<12-12, 2+8>, or <0, 10>.

In terms of i and j, that'd be 0i + 10j, or just 10j.

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AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear
VMariaS [17]

Answer:

\overline{QT}

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides A(x_1,y_1) and B(x_2,y_2) in the ratio m:n=3:2

The x-coordinate is given by:

x=\frac{mx_2+nx_1}{m+n}

The y-coordinate is given by:

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AB has coordinates A(-5,9) and B(7,- 7)

We substitute the values to get:

x=\frac{3*7+2*-5}{3+2}

x=\frac{21-10}{5}

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and

y=\frac{3*-7+2*9}{3+2}

y=\frac{-21+18}{5}

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Therefore C has coordinates  (\frac{11}{5},-\frac{3}{5})

The line segment that contains C is \overline{QT}

See attachment.

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Linear function whose graph has a slope of 7
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y=7x?

Step-by-step explanation:

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Read 2 more answers
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