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Juliette [100K]
3 years ago
14

Helpp, I need to determine the slope and y-intercept for each group. I need to write an equation for the graph in slope-intercep

t form.

Mathematics
2 answers:
jenyasd209 [6]3 years ago
4 0

Answer:

Slope = -2

Y intercept = 4

Equation. y = -2x +5

Step-by-step explanation:

Using points, (1,2) and (3,-2)

Slope = (-2-2)/(3-1) = -4/2 = -2

Y intercept = 4

-2 = (y-3)/(x-1)

-2(x-1) = y-3

-2x +2 = y-3

y = -2x +2 +3

y = -2x +5

Phoenix [80]3 years ago
3 0
Rise over run, -2/1. The slope is -2

Y intercept is 4

Y =-2x + 4
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Dagogo uploads 3 videos on his channel every month. Each video averages 15 minutes in length and gets an average of 150,000 new
Lana71 [14]

Answer: 20 months

Step-by-step explanation:

x months times y for views over 1 month = 9000000 views

3 x 150000(views per video) = 450000

9000000/450000= 20 months

4 0
2 years ago
Realiza estas operaciones y expresa el resultado en metros 1m-(5dm3cm) (2hm4m)+35dam (3hm6dam)+(8dam5m) (2m5dm6cm)-85cm
ivolga24 [154]

Answer:

126.109,63 m

Step-by-step explanation:

Por conveniencia, todas las unidades se convierten a m

1000 m = 1 km

100 m = 1hm

10m = 1 presa

1 m = 1 m

10dm = 1m

100 cm = 1 m

1000 mm = 1 m

1m- (5dm3cm) (2hm4m) + 35dam (3hm6dam) + (8dam5m) (2m5dm6cm) -85cm

= 1m- (5/10 +3/100) (2 * 100 + 4m) + 35 * 10 (3 * 100 + 6 * 10) + (8 * 10 + 5m) (2m + 5/10 + 6/100 ) -85/100

= 1 m- (0.5 +0.03) (200 + 4m) +350 (300 +60) + (80 + 5m) (2m + 0.5 + 0.06) -85/100

= 1 m- (0,53) (204 m) +350 (360) + (85 m) (2,56) -85/100

= 1 m- (108,12 m) +126000+ (217,6) - 0,85

= 126.109,63 m

For convenience all units are converted to m

1000m = 1km

100 m= 1hm

10m = 1 dam

1m= 1m

10dm= 1m

100 cm= 1 m

1000 mm= 1m

1m-(5dm3cm) (2hm4m)+35dam (3hm6dam)+(8dam5m) (2m5dm6cm)-85cm

= 1m-(5/10 +3/100) (2*100 +4m)+35*10 (3*100 +6*10)+(8*10+5m) (2m+5/10+6/100)-85/100

= 1m-(0.5 +0.03) (200 +4m)+350 (300 +60)+(80+5m) (2m+0.5+0.06)-85/100

= 1m-(0.53) (204m)+350 (360)+(85m) (2.56)-85/100

= 1m-(108.12m)+126000+(217.6)- 0.85

= 126,109.63 m

5 0
3 years ago
Thời gian vận chuyển hàng hóa trên tuyến đường AB là biến ngẫu nhiên X có phân phối
Goshia [24]

Answer:

Thời gian vận chuyển hàng hóa trên tuyến đường AB là biến ngẫu nhiên X có phân phối

chuẩn với trung bình   5 giờ, độ lệch chuẩn   0, 25 giờ.

a. Chuyến có thời gian lớn hơn 5,2 ( ) /100   a b  giờ được xem là trễ, tính tỉ lệ chuyến trễ?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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11111nata11111 [884]

Answer:

A is reflected over the y axis and translated 2 units up and 2 units to the right.

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7 0
3 years ago
Read 2 more answers
A shipping container will be used to transport several 120-kilogram crates across the
allochka39001 [22]

Answer:

150.833... or 150 and 5/6 crates

Step-by-step explanation:

We can create an equation to solve this.

Let x represent the number of 120 kilogram crates that can be loaded into the chipping container.

120x (weight of the crates) + 5900 (weight already in the container) = 24000 (max weight in the container)

We'll start by subtracting 5900 from both sides to try to isolate x, the number of containers we still need to meet 24000 kilograms.

120x = 18100

Now we just have to isolate x by dividing by 120.

x = 150.83333333333333333333333333333

If you want to use a mixed fraction form for this solution since the 3's keep repeating, it would be 150 and 5/6 crates.

4 0
2 years ago
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