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Juliette [100K]
3 years ago
14

Helpp, I need to determine the slope and y-intercept for each group. I need to write an equation for the graph in slope-intercep

t form.

Mathematics
2 answers:
jenyasd209 [6]3 years ago
4 0

Answer:

Slope = -2

Y intercept = 4

Equation. y = -2x +5

Step-by-step explanation:

Using points, (1,2) and (3,-2)

Slope = (-2-2)/(3-1) = -4/2 = -2

Y intercept = 4

-2 = (y-3)/(x-1)

-2(x-1) = y-3

-2x +2 = y-3

y = -2x +2 +3

y = -2x +5

Phoenix [80]3 years ago
3 0
Rise over run, -2/1. The slope is -2

Y intercept is 4

Y =-2x + 4
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For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

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(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

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(c) At least 2 will have invalid licenses.

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P(X < 2) + P(X \geq 2) = 1

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P(X \geq 2) = 1 - P(X < 2)

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P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

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