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Bumek [7]
3 years ago
10

PLEASE HELP ASAPP WRONG ANSWERS GET REPORTED GOOD ANSWERS GET BRAINLIEST, THANK YOU :)

Mathematics
1 answer:
Helen [10]3 years ago
7 0
(9) The correct Option is (C) 4, -3

Explanation:
The left hand limit is:
\lim_{x \to 2^-} f(x) = +4

+4 because the line(y=+4) is constant if limit approaches to 2 (from left side of the graph)


The right hand limit is:
\lim_{x \to 2^+} f(x) = -3

-3 because the line(y=-3) is constant if limit approaches to 2 (from the right side of the graph)

So the correct Option is (C) 4, -3

(10) The correct Option is (C) -4

Explanation:
\lim_{x \to 3^+} f(x) = -4

The plus sign in the limit indicates that it is the right hand limit. So we have to approach to 3 from the right side of the graph. When we do that, we see the constant line y = -4. Hence the correct option is (C)

NOTE: Although the question seems complex because there is slope involved but in this particular case, the examiner is concerned about the right hand limit. If she or he asks the left hand limit(3-minus) then we would take the slope-line.

P.S. Sorry for bit late reply! I thought somebody answered it already! :)
You might be interested in
a rectangular plot of land 8m long and 6m wide.there is a flower bed in the form of a circle of radius 3m.find 1.area of land. 2
mixer [17]

Answer:

1)Area of the Land  is 48 square meters

2) Area of flower bed   is  28.26 square meter

3)Area of land excluding flower bed   is 19.74 square meters

4)cost of planting grass in land  excluding flower bed   is Rs 118.44

Step-by-step explanation:

Given:

Length of the Rectangular plot = 8m

Width of the rectangular plot =  6m

Radius of the circular flower bed = 3m

1)Area of the Land  

Area of the Rectangular plot  = Area of the Land  

Area of the Land   = length x width

Area of the Land   =  8*6

Area of the Land  = 48 square meters-----------------------------(1)

2. Area of flower bed

Area of flower bed =  4 x area of one quadrant

Area of flower bed =  area of the circle

Area of flower bed  = \pi r^2

where r is the radius

Now , substituting the values

Area of flower bed = \pi (3)(3)

Area of flower bed = 28.26 square meters-----------------------------(2)

3)Area of land excluding flower bed

Area of land excluding flower bed =  Area of the rectangular land - area of flower beds

Area of land excluding flower bed =  48 - 28.26

Area of land excluding flower bed = 19.74 square meters

4)cost of planting grass in land

Cost of planting grass per square meter = 6

Excluding the flower bed we have  19.74 square meters. to plant grass  for this 19. 74 square meters, the cost will be

=19. 74 \times 6

= Rs 118.44

6 0
3 years ago
In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes
ale4655 [162]

Answer:

The sample mean is \bar{x}=14.371 min.

The sample standard deviation is \sigma = 18.889 min.

Step-by-step explanation:

We have the following data set:

\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

\bar{x} = \frac{{\sum}x}{n}

where, n is the number of values in the data set.

\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }

The mean of a sample is  \bar{x}=14.371.

Create the below table.

Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889

7 0
3 years ago
The ratio of fishing boats to sailboats in a bay is 8:3. There are a total of 24 sailboats in the bay. How many fishing boats ar
lianna [129]

Answer:

The number of fishing boats in the bay = 64.

Step-by-step explanation:

The total number of sailboats  = 24

Let us assume the number if fishing boats in the bay = m

⇒ Ratio of fishing boats to sailboats in a bay =  m  :  24.

Now, the ratio of fishing boats to sailboats in a bay is 8  :  3.

So, by the RATIO OF PROPORTION:

\frac{m}{24}  = \frac{8}{3}  \implies m = \frac{8}{3} \times 24 = 64

⇒  m = 64

Hence the number of fishing boats in the bay = 64.

6 0
3 years ago
CAN ANYBODY HELP ME OUT
bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

7 0
3 years ago
Solve the equation plz and thx
kodGreya [7K]
It is A bro 4 eso a huevo
5 0
3 years ago
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