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faltersainse [42]
4 years ago
13

At 9:00 on Saturday morning, two bicyclist pass each other on a bicycle path. The bicyclist heading north is riding 5km/h faster

then the bicyclist heading south. At 10:30, (1.5 hours later) they are 49.5 km apart. Find the two bicyclists’ rates.
Mathematics
1 answer:
natita [175]4 years ago
5 0

Answer:

Step-by-step explanation:

One rider's rate is x....the other is x+4

Once they pass each other, they travel for 1.5 hrs...and the combined distance they travel = 39 km

So....Rate x Time = Distance....and we have

x(1.5) + (x+4)(1.5) = 39 simplify

1.5x + 1.5x + 6 = 39

3x + 6 = 39 subtract 6 from both sides

3x = 33 divide by 3 on both sides

x = 11 km/hr this si the slower rider's rate

x + 4 = 11 + 4 = 15 km/hr and this is the faster rider's rate

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hichkok12 [17]
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Nadya [2.5K]

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8 0
3 years ago
In a parallel circuit, ET = 240 V, R = 47 kΩ, and XL = 50 kΩ. What is the reactive power?
Fittoniya [83]

Answer:

Reactive power is 1.152 VARs

Step-by-step explanation:

We are given that in a parallel circuit,E_{T}=240V,R=47kΩ and X_{L}=50kΩ.

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3 years ago
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pochemuha

Answer:

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