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2 years ago

What is the radius of a circle with circumference 56 inches

Mathematics

1 answer:

pochemuha2 years ago

5 0

Answer:

The answer is 8.91 or 8.9

Step-by-step explanation:

SInce the circumference is 56, you'll divide it by pi or 3.14. It's as if you're doing it backwards, but not always. After you divide it by 3.14, you'll get your diameter, or in this case, 17.8. Divide the diameter by 2 because the diameter is twice the radius. Eventually your final answer will be 8.91 or 8.9

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Beef hope me I need you to answer the question. What is n * 54 - 688-20 =???³

blsea [12.9K]

Answer:n= 1/3d - 2/3m

Step-by-step explanation:

d=2m+3n

Step 1: Flip the equation.

2m+3n=d

Step 2: Add -2m to both sides.

2m+3n+−2m=d+−2m

3n=d−2m

Step 3: Divide both sides by 3.

3n/3 = d-2m/3

Therefore

n= 1/3d - 2/3m

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Answer

maxtext75

Helping Hand

15 answers

26 people helped

Answer:

n = d - 2m

Step-by-step explanation:

First we want to get n alone on one side, so we should subtract 2m from both side;

d = 2m + 3n

3n = d - 2m

Now to get n by itself, we need to divide by 3 from both sides;

3n = d - 2m

n = d - 2m

*Pretend there is a fraction bar between d - 2m and 3

Step-by-step explanation:

7 0

3 years ago

Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$