The amount invested at 11% is $5,000
The amount invested in stock is $14,000
What is the net profit on both investments?
The profit of each investment is the rate of return or loss multiplied by the amount invested
Let us assume that x was invested at 11% and the remaining 19000-x was invested at a loss rate of 3%
net profit=(11%*x)+(19000-x)*-3%
net profit=130
130=(11%*x)+(19000-x)*-3%
130=0.11x-570+0.03x
130=0.14x-570
130+570=0.14x
700=0.14x
x=700/0.14
x=$5,000
Amount invested in stock=19000-x
Amount invested in stocks=19000-5000
Amount invested in stocks=$14,000
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4(x-1)=-4+4x
4x-4=-4+4x
-4x -4x
-4=-4
Not sure what the problem was asking, but it’s solvable!
Answer:
D: 768
Step-by-step explanation:
First, he divides a piece of paper in half.

He gets two pieces.
Next, he cuts each of the pieces into three parts.

Thirdly, he cuts each of the 6 pieces into 8 pieces.

Lastly, he divides each piece into 16 parts.

He has 768 pieces in the end. (D)
Answer:
It's answer is 8
Step-by-step explanation:
hypotenuse (h) = 10
base (b) = 6
perpendicular (p) = x = ?
We know by using Pythagoras theorem
p = √ h² - b²
= √ 10² - 6²
= √ 100 - 36
= √ 64
x = 8
Hope it will help : ) ❤
<span>
<u><em>The correct answer is: </em></u>1000.
<u><em>Explanation</em></u><span>
<u><em>: </em></u>We divide to find the answer to this: </span></span>

<span><span>. When we are dividing by 10, we can move the decimal to the left one place; doing this gives us 1000.</span></span>