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cricket20 [7]
3 years ago
7

HELP PLEASE, I don't know what I am doing...

Mathematics
1 answer:
kari74 [83]3 years ago
5 0
I can only jelp u with the first one i think it's going to be 7 because 7*2= 14
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Please help me i rlly need help
Mumz [18]

Answer:

3

Step-by-step explanation:

Given a line with points; (2, 5) (3, 8).

1. Find the slope of the given line

The formula for finding the slope is:

\frac{y_{2}-y_{1} }{x_{2} - x_{1}}

Substitute in the values;

x_{1} = 2\\y_{1} = 5\\x_{2} = 3\\y_{2} = 8

\frac{8-5}{3-2}

simplify;

\frac{3}{1}

= 3

2. Find the slope of the parallel line;

Remember, when two lines are parallel, they run alongside each other, of infinitely long, but they never touch. Hence two parallel lines have the same slope. Therefore, the slope of a line that is parallel to the given one will also have the same slope as the given one, which is 3.

5 0
3 years ago
what is the equation of the line that is parallel to the line y - 2x - 1 and passes through the point (2,7)?
zvonat [6]

Answer:

y= 2x +3

Step-by-step explanation:

5 0
3 years ago
Please help.
serious [3.7K]

The number of throws that the player make X follows binomial distribution.

The probability that the player makes x throws out of eleven throws is

P(X=x)=C(x,11)0.5^x(0.5)^{11-x}=C(x,11)0.5^{11}

The probability that the player makes at most nine out of eleven free throws

is

\sum_{x=0}^9C(x,11)0.5^{11}=1-\sum_{x=10}^{11}C(x,11)0.5^{11}\\ =1-C(10,11)0.5^{11}-C(11,11)0.5^{11}=1-\frac{12}{2^{11}} \\ =1-\frac{3}{512} =\frac{509}{512}

Correct choice is (B).

8 0
3 years ago
a baker orders 162 eggs. each cartoon contains 18 eggs. which equation can you use to find the number x of cartoons?
Oxana [17]
18x = 162

x = 9

There are 9 cartons filled with 18 eggs each, which is 162 eggs in total.
4 0
3 years ago
Please help me I really don't know
Rama09 [41]

Answer:

(1,2)

Step-by-step explanation:

The other intervals contain local minimums, local maximums are also known as maximum points and look like upwards parabolas

4 0
3 years ago
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