Who else thinks this is kinda a school social media??

How many bananas are needed to make the third scale balance?

frozen [14]

The number of bananas required to make the third scale balance is 3.

<h3>What is a scale?</h3>

A scale is a tool used for weighting objects. If the objects on each side weigh the same the scale is balanced. Based on this, let's determine the possible weight of each fruit to balance the last scale.

Scale 1 (10 bananas/ 2 pineapples)

It is known 10 bananas weigh as much as 2 apples, but to solve this problem let's assume 10 bananas weigh a total of 1000 grams.

10 banans = 1000 grams = each banana weighs 100 grams
2 pineapples = 1000 grams = each pineapple weighs 500 grams

Scale 2 ( 1 pineapple / 2 bananas, 1 apple)

Using the same imaginary weights let's find the weight of the apple.

1 pineapple = 500 grams
2 bananas = 200 grams
1 apple = 300 grams (500 - 200 = 300)

Scale 3 (1 apple /x )

We know 1 apple is equal to 300 grams and 1 banana is equal to 100 grams. Based on this, the number of bananas to balance the scale is 3.

Learn more about balance in: brainly.com/question/7181548

8 0

2 years ago

The drawing plan for an art studio shows a rectangle that is 15.2 inches by 8 inches. The scale in the plan is 4 in.: 5 ft. Find

Kamila [148]

Answer:

Length: 19 feet

Width: 10 feet

Area: 190 feet $x^{2}$

Step-by-step explanation:

This is a question about ratio.

Length: let $x$ be the actual length.

$15.2 : x = 4 : 60$

$x = 19$

Width: let $y$ be the actual width.

$8 : y = 4 : 60$

$y = 10$

Area: A = xy

$19 * 10 = 190$

3 0

3 years ago

Which is a solution to the equation 6 x + y = 4<br><br>1, -10 <br>2, -8<br>2, 8<br>1, 2

NISA [10]

Answer:

1,-10 and 2,-8

Step-by-step explanation:

If you substitute each answer choice:

6+-10=4

12+-8=4

12+8=4

6+2=4

The only ones that would make sense are the first and second one.

4 0

3 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

(c) What is Upper P ( $\overline{X}$ less than or equals 74.4 ) =

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$