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AVprozaik [17]
2 years ago
5

The incomplete table below summarizes the number of left-handed students and right-handed students by gender for the eighth-grad

e students at Keisel Middle School. There are 5 times as many right-handed female students as there are left-handed female students, and there are 9 times as many right-handed male students as there are left-handed male students. if there is a total of 18 left-handed students and 122 right-handed students in the school, which of the following is closest to the probability that a right-handed student selected at random is female? (Note: Assume that none of the eighth-grade students are both right-handed and left-handed.)
A) 0.410
B) 0.357
C) 0.333
D) 0.250

Mathematics
1 answer:
vova2212 [387]2 years ago
7 0

Answer: A) 0.410

In order to solve this problem, you should create two equations using two variables (x and y) and the information you're given. Let x be the number of left-handed female students and let y be the number of left-handed male students. Using the information given in the problem, the number of right-handed female students will be 5x and the number of right-handed male students will be 9y. Since the total number of left-handed students is 18 and the total number of right-handed students is 122, the system of equations below must be true:

x+y=18

5x+9y=122

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<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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Divisor = 6.3               [denominator]

If 26.97 ÷ 6.3 is written in long division form so that the divisor is written as a whole number, we have the following;

(i)First convert the divisor to a whole number by multiplying by 10 i.e

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(ii) Since the divisor (denominator) has been multiplied by 10, to make sure the division expression stays the same, we need to multiply the dividend(numerator) too by 10. i.e

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