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Vilka [71]
3 years ago
8

Are one of these irrational? If so which one? 0.333... 0.020202... 0.8

Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

None

Step-by-step explanation:

All of these numbers can be expressed as fractions, therefore they are all rational.

0.333... = ¹/₃

0.020202... = ²/₉₉

0.8 = ⁴/₅

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verbally explain how to obtain the graph of the quadratic function f(x)=-2(x+3)^2-4 from the graph of y=x^2.
Ksivusya [100]

Answer:

The graph f(x)=-2(x+3)^2-4 is a reflection over the x-axis, vertical stretch by a factor of 2, a horizontal translation left 3 units and a vertical translation 4 units down of the graph y=x^2.

Step-by-step explanation:

The graph f(x) is reflected over the x-axis because the negative is outside of the parenthesis.

it's a vertical stretch by a factor of 2 because 2 is outside of the parenthesis and is greater than 1.

(x+3) is a horizontal translation left 3 units because it is inside the parenthesis.

-4 is vertical translation 4 units down because it is outside of the parenthesis.

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3 years ago
. Given that O is the centre of the following circle, find the values of the unknowns.​
alex41 [277]

Given:

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To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

a^{2} + 5^{2} = 13^{2}

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a^{2} = 169 - 25

a^{2} = 144

\sqrt{a^{2}}=\sqrt{144}

a = 12

Now to find the value of 'b', i will use law of cosine,

c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }

12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta =   0.3846\\\beta  = cos^{-1}(0.3846)\\\beta = 67.38

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

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Step-by-step explanation:

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