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tensa zangetsu [6.8K]

3 years ago

10

a pair of socks costs $5.00. a package of 3 pairs costs $12.00. how much would you save if you buy 2 packages instead of 6 indiv

idual pairs?

1 answer:

svp [43]3 years ago

7 0

you will save 6 dollars If you buy 2 packages, instead if 6 individual pairs.

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Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)

zloy xaker [14]

Answer:

A)

$k=0$

B)

$\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}$

C)

$\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}$

Step-by-step explanation:

We are given the function:

$\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}$

A)

Given that h(1) = 20, we want to find <em>k</em>.

h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

$\displaystyle (20) = 20e^{k(1)}$

Simplify:

$1= e^k$

Anything raised to zero (except for zero) is one. Therefore:

$k=0$

B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

$\displaystyle (40) = 20e^{k(1)}$

Simplify:

$\displaystyle 2 = e^{k}$

We can take the natural log of both sides:

$\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}$

By definition, ln(e) = 1. Hence:

$\displaystyle k = \ln 2$

Therefore:

$2k+1 = 2\ln 2+ 1 \approx 2.3863$

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

$\displaystyle (10) = 20e^{k(1)}$

Simplfy:

$\displaystyle \frac{1}{2} = e^k$

Take the natural log of both sides:

$\displaystyle \ln \frac{1}{2} = k\ln e$

Therefore:

$\displaystyle k = \ln \frac{1}{2}$

Therefore:

$\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931$

3 0

2 years ago

Find the exact solution to the equation. 7-log2(x+5) = 6

Sindrei [870]

Answer:

x = -3

Step-by-step explanation:

You can try the answers to see which works. Or, you can actually solve the equation for x.

... 7 - log2(x+5) = 6

... 1 - log2(x+5) = 0 . . . . subtract 6

... 1 = log2(x+5) . . . . . . . add log2(x+5)

... 2 = x +5 . . . . . . . . . . . take the antilog

... -3 = x . . . . . . . . . . . . . subtract 5

5 0

2 years ago

Write a function rule in terms of x and y for the line that contains the points (-7.4, -9.7) and ( 8.4, 6.1) .

Karo-lina-s [1.5K]

Answer:

y = x + -2.3

x = -y - 2.3 (but why would one need this?...)

Step-by-step explanation:

(6.1 - (-9.7))/(8.4 - (-7.4)) = 15.8/15.8 = 1

6.1 = 8.4 + b

b = -2.3

8 0

2 years ago

Han has 5 pencils and Andre has 8

Tatiana [17]

Answer:

That's all I could think that you might need. Finish your question please

Step-by-step explanation:

Together: 13

Andre has 3 more

4 0

3 years ago

What is the additive identity of rational number

Burka [1]

Answer:

zero(0)

Step-by-step explanation:

The additive identity of a set of number is a number such that the its sum with any of the numbers in the set would give a result that is equal to the number in that set.

In other words, say for example the set of numbers is rational, the additive identity of rational numbers is 0. This is because, given any rational number say <em>x</em>, adding zero to the number <em>x</em> gives the same number <em>x. </em>i.e

x + 0 = x

If x is say 2, then we have;

2 + 0 = 2

Since adding zero to rational numbers gives has no effect on the numbers, then zero (0) is the additive identity of rational numbers.

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3 0

3 years ago