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tensa zangetsu [6.8K]
3 years ago
10

a pair of socks costs $5.00. a package of 3 pairs costs $12.00. how much would you save if you buy 2 packages instead of 6 indiv

idual pairs?
Mathematics
1 answer:
svp [43]3 years ago
7 0
you will save 6 dollars If you buy 2 packages, instead if 6 individual pairs.
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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
Last month you went on three hikes. One hike was 2 ¾ miles long, one was 1 ½ miles long, and the other was 3 ⅜ miles long. In de
kap26 [50]
I'm not really a big fraction type person, but I'm sure it's 7.625
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3 years ago
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I Dont understand what to do
Sati [7]
You need to find the area of this
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3 years ago
Let x²y +ay² = b be an Implicitly defined function, where a and b are fixed Constants; find dy/dx
geniusboy [140]

The value of the differential with respect to x is -xy/x²+ay

<h3>Implicit differentiation</h3>

Given the following function

x²y +ay² = b

We are to differentiate implicitly with respect to x

x²dy/dx + 2xy + 2aydy/dx = 0

(2x²+2ay)dy/dx = -2xy
dy/dx = -xy/x²+ay

Hence the value of the differential with respect to x is -xy/x²+ay

Learn more on implicit differentiation here: brainly.com/question/25081524

#SPJ1

3 0
2 years ago
Pls answer! i will mark brainliest!
Volgvan

Answer:

3 inches

Step-by-step explanation:

(14+2x) × (15+2x) = 2(14×15)

210 +30x +28x + 4x² = 420

4x² + 58x - 210 = 0

2x² + 29x - 105 = 0

2x² + 35x - 6x - 105 = 0

x(2x + 35) - 3(2x + 35) = 0

(x - 3)(2x + 35) = 0

x = 3, -35/2(not possible)

3 0
3 years ago
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