Answer:
Confused as well
Step-by-step explanation:
If there are hypothetically 10 hours a day with 100 minutes an hour and 100 seconds per minute
at 6 pm there would be 18 hours gone in the day
18 normal hours are equal to 18*60*60 = 64800 seconds
(64800 seconds) / 10000 ( for hours)
6:48 would be the replacement time
but this answer is wrong bc it's not an option
Answer:
No order Pair fall on the graph
Step-by-step explanation:
The given Function is
...............(i)
Now to see whether these ordered pairs Lay on it we will put each ordered pair in the equation (i)
Lets take first ordered pair (1,1)
here x = 1
putting it in (i) gives

this is not equal to 1 so the order pair (1,1) does not fall on function 
Lets take second ordered pair (-1,-4)
here x = -1
putting it in (i) gives

this is not equal to -4 so the order pair (-1,4) does not fall on function 
Lets take third ordered pair (-2,-1/8)
here x = -2
putting it in (i) gives

this is not equal to -1/8 so the order pair (-2,1/8) does not fall on function 
Lets take fourth ordered pair (0,-1/2)
here x = 0
putting it in (i) gives

this is not equal to -1/2 so the order pair (0,-1/2) does not fall on function 
The time changes depending on how fast the truck is going-so it's dependent
50 miles and the truck do not change no matter what-so they are constant
The speed of the truck changes the time-so the speed is the independent
<u>Answer with step-by-step explanation:</u>
We are given that Sam invested $48,000 at 6% interest and the rest at 10%. Given that he received $4,000 interest in one year, we are to find how much he invest at each rate.
Assuming the amount invested at 6% interest rate as
, we can write it as:
![(\frac{6}{100} \times x)+(\frac{10}{100} \times [48000-x])=4000](https://tex.z-dn.net/?f=%28%5Cfrac%7B6%7D%7B100%7D%20%5Ctimes%20x%29%2B%28%5Cfrac%7B10%7D%7B100%7D%20%5Ctimes%20%5B48000-x%5D%29%3D4000)





So the amount invested at 6% = $20,000 and amount invested at 10% = (48000 - 20000) = $28,000