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3 years ago

8

Water from a leaking faucet is dripping into a cylindrical cup. The height of water in inches, y, after x hours is graphed below

.

1 answer:

noname [10]3 years ago

5 0

Answer:bxbs

Step-by-step explanation:

Jdjd

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in triangle PQR the measure of angle R=90, QP=73, RQ=55, and PR=48. what is the value of the sine of angle P to the nearest Hund

alexandr402 [8]

Answer:

P ≈ 48.89°(nearest hundredth)

Step-by-step explanation:

The triangle PQR forms a right angle triangle since angle R is 90°. The triangle has an hypotenuse , adjacent and opposite side.

Using the SOHCAHTOA principle one can find the sine ratio of angle P. Let us designate where each side represent.

opposite side(QR) = 55

adjacent side(PR) = 48

hypotenuse(PQ) = 73

sin P = opposite/hypotenuse

sin P = 55/73

P = sin⁻¹ 55/73

P = sin⁻¹ 0.75342465753

P = 48.8879095605

P ≈ 48.89°(nearest hundredth)

5 0

3 years ago

The circumference of a circle is 9π m. What is the area of the circle? ASAP!

liubo4ka [24]

Answer:

20.25 m²

Step-by-step explanation:

the area (A) and circumference (C) of a circle are calculated using the formulae

C = 2πr and A = πr² ( where r is the radius )

calculate the radius using the formula for circumference

2πr = 9π ( divide both sides by 2π )

r = $\frac{9\pi }{2\pi }$ = $\frac{9}{2}$ = 4.5, hence

A = π × 4.5² = 20.25π m²

4 0

3 years ago

What is the product in simplest form? State any restrictions on the variable. Please show your work.

mote1985 [20]

You have the following expressions given in the problem above:

(y^2/y-3)(y^2-y-6/y^2+y)

By applying the exponents properties, you can simplify it, as it shown below:

(y^2/y-3)(y^2-y-6/y^2+y)
(y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
(y^4-y^3-6y^2)/(y^3-2y2-3y)

Then, you have:
y^2(y^2-y-6)/y(y^2-2y-3)
(y^2-y-6)/(y^2-2y-3)

The answer is: (y^2-y-6)/(y^2-2y-3)

5 0

3 years ago

Read 2 more answers

I just need these questions answered, there is no requirement for any explanation! If anybody could assist, that would be great!

koban [17]

Answer:

See explanation

Step-by-step explanation:

Q9. Statement Reason

1) $\angle ABD \cong \angle CBD$ Given

2) $\overline{AB}\cong \overline{CB}$ Given

3) $\overline{BD}\cong \overline {BD}$ Reflexive property

4) $\triangle ABD\cong \triangle CBD$ SAS postulate

5) $\angle A\cong \angle C$ Corresponding parts of congruent triangles are congruent.

Q8. Statement Reason

1) $\overline{AD}\parallel \overline{BC}$ Given

2) $\angle A\cong \angle C$ Alternate interior theorem

3) $\angle AED\cong \angle CEB$ Vertical angles theorem

4) $\overline{AE}\cong \overline{EC}$ Given

5) $\triangle AED\cong \triangle CEB$ ASA postulate

Q7.

1) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\overline{AB}\cong \overline{DE}$

The postulate or theorem that can be used to prove the triangles are congruent:

SAS postulate

2) $\overline{BC}\cong \overline {EF}$ - Given

$\overline{AC}\cong \overline {DF}$ - Given

Pairs of needed sides or pair of needed angles:

$\overline{AB}\cong \overline{DE}$

The postulate or theorem that can be used to prove the triangles are congruent:

SSS postulate

3) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\angle ACB\cong \angle DFE$

The postulate or theorem that can be used to prove the triangles are congruent:

ASA postulate

4) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\angle CAB\cong \angle FDE$

The postulate or theorem that can be used to prove the triangles are congruent:

AAS postulate

Q10. Statement Reason

1) $\angle MCI\cong \angle AIC$ Given

2) $\overline{MC}\cong \overline{AI}$ Given

3) $\overline{CI}\cong \overline{CI}$ Reflexive property

4) $\triangle MCI\cong \triangle AIC$ SAS postulate

4 0

3 years ago

Describe the Distributive Property and give an example of how it works.

slamgirl [31]

The distributive property of multiplication over addition can be used when you multiply a number by a sum. For example, suppose you want to multiply 3 by the sum of 10 + 2. 3(10 + 2) = ? According to this property, you can add the numbers and then multiply by 3.

5 0

3 years ago