If h(x) = −x − 10, find h(−2). (1 point) −20 1.6 −1 0

PLEASE HELP IMAGE IS BELOW!!

guajiro [1.7K]

Answer:

Number of small boxes shipped = 7

Number of large boxes shipped = 15

Step-by-step explanation:

Let the number of small boxes = s

And the number of large boxes = l

Weight of small box = 25 pound

Weight of the large box = 50 pounds

Total weight of the shipment = 925 pounds

Therefore, equation for the weight of shipment will be,

25s + 50l = 925

s + 2l = 37 ----- (1)

Total number of boxes shipped = 22 boxes

Therefore, equation will be,

s + l = 22 ------(2)

Subtract equation (2) from equation (1)

(s + 2l) - (s + l) = 37 -22

l = 15

From equation (2)

s + 15 = 22

s = 7

Therefore, number of small boxes shipped = 7

Number of large boxes shipped = 15

6 0

3 years ago

HELP ME PLZZ, ASAP!! In your own words explain what a Cross Section is.

wariber [46]

Answer:

A cross section is a surface or shape that is exposed by making a straight cut through something especially at right angles to an axis.

4 0

3 years ago

Sarah plans to sell homemade birdhouses at the local craft fair. She spent $90 on new tools and estimates that she spends $6 in

Lapatulllka [165]

Answer: C
Y=90+6x/x

90 new tools + 6 dollars (x) over x dollars

5 0

3 years ago

Read 2 more answers

The perimeter of an isosceles triangle is 15.6m. Find the lengths of its sides, if: The base is 3m smaller than a leg ____m, ___

zlopas [31]

Leg 1 is 15.6 meters. 15.6-3 is 12.6. And the last leg is 15.6

8 0

3 years ago

Read 2 more answers

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

4 years ago