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solong [7]
3 years ago
12

What is the point-slope form of an equation passing through (0, -5) with a 5 points

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

y=2x-5

Step-by-step explanation:

y-y_{1}=m(x-x_{1})

x_{1}=0, y_{1}=-5\\, and m=2

y-(-5)=2(x-0), -(-5)-Two negatives make it positive, and you distribute the 2

y+5=2x, you now subtract 5 to get y by itself to get your answer of

y=2x-5

*NOTE* (0,-5) is the y-intercept, so you could have used the linear equation of y=mx+b, m=2, and b(y-intercept)=-5

giving you y=2x-5

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To avoid confusion in using the word "particle," one must state that a particle is an identifiable part of dust, a molecule, an atom, or an electron.  This means that particles form these elements.

Step-by-step explanation:

For example, atoms are made up of three particles: protons, neutrons and electrons.  These particles are each composed of even smaller particles known as quarks.  Since quarks cannot be broken down further, they are the smallest particles known to mankind.

8 0
3 years ago
A school counselor surveyed 90 randomly selected students about the languages they speak. Of the students surveyed, 15 speak mor
son4ous [18]

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b

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Roberto brought 413 boxes of carrot muffins for a bake sale. Jose brought 3 34 boxes of apple muffins.
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8 0
3 years ago
(k) is 1/8. What is the value of y when x is 12?
mafiozo [28]
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8 0
3 years ago
Please help me on these two questions
leonid [27]
<h2>1. FIRST QUESTION.</h2>

M is directly proportional to r^3

Suppose you have two variables, say, x \ and \ y. We say that y varies directly as x or, in other words, y is directly proportional to x if and only if:

y=kx

Where k is a nonzero constant called the constant of proportionality.

Knowing this, we can solve this problem. Here M is directly proportional to r^3. So:

M=kr^{3}

We know that when r=4, \ M=160, hence the constant of proportionality can be found as follows:

M=kr^{3} \\ \\ 160=k(4^3) \\ \\ 160=k(64) \\ \\ Solving \ for \ k: \\ \\ k=\frac{160}{64} \therefore k=\frac{5}{2}

So:

M=\frac{5}{2}r^3

<h3>PART A)</h3>

When r=2, then:

M=\frac{5}{2}(2^3) \\ \\ M=\frac{5}{2}(8) \\ \\ \boxed{M=20}

<h3>PART B)</h3>

When M=540, then:

540=\frac{5}{2}(r^3) \\ \\ r^3=\frac{2(540)}{5} \\ \\ r^3=216 \\ \\ r=\sqrt[3]{216} \\ \\ \boxed{r=6}

<h2>2. SECOND QUESTION.</h2>

M is directly proportional to r^2

We know that when r=2, \ M=14, hence the constant of proportionality is:

M=kr^{2} \\ \\ 14=k(2^2) \\ \\ 14=k(4) \\ \\ Solving \ for \ k: \\ \\ k=\frac{14}{4} \therefore k=\frac{7}{2}

So:

M=\frac{7}{2}r^2

<h3>PART A)</h3>

When r=12, then:

M=\frac{7}{2}(12^2) \\ \\ M=\frac{7}{2}(144) \\ \\ \boxed{M=504}

<h3>PART B)</h3>

When M=224, then:

224=\frac{7}{2}(r^2) \\ \\ r^2=\frac{224(2)}{7} \\ \\ r^2=64 \\ \\ r=\sqrt{64} \\ \\ \boxed{r=8}

8 0
3 years ago
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