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Sergio [31]
3 years ago
7

A designer creates a drawing of a triangular sign on centimeter grid paper for a new business. The drawing has sides measuring 6

cm, 8 cm, and 10 cm, and angles measuring 37 degrees, 53 degrees and 90 degrees. To create the actual sign shown, the drawing must be dilated using a scale factor of 40.
Find the lengths of the sides of the actual sign.
Find the angle measures of the actual sign.
The drawing has the hypotenuse on the bottom. The business owner would like it on the top.
describe 2 transformations that will do this.
The shorter leg of the drawing is currently on the left. It needs to remain on the left after the hypotenuse goes to the top. Describe which transformation will accomplish this?

PLZZZZ HELP THANK YOU
Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
The actual length is 6*40=240 cm, 8*40=320 cm, 10*40=400 cm. And the angle measures of the actual sign will not change. The transformation can be turning over using the hypotenuse as axle. Or rotate the triangular sign 180° using the center of the triangle as the center of rotation. The turning over method will accomplish.
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tatuchka [14]
Area of the base and the top :(4x7) + (4x7) = 56
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Lateral area of the right & left = (7x12) + (7x12) = 168

TOTAL AREA = 56+96+168 = 320

Volume = 4x7x12 = 336 

RATIO AREA/VOLUME = 320/336 . Simplify by dividing numerator and denominator by 16. Final result: AREA/VOLUME = 20/21


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