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suter [353]
2 years ago
8

Frederick asked a bank teller to cash a $390 check using $20 and $50 bills. If the teller gave

Mathematics
2 answers:
Vadim26 [7]2 years ago
6 0

12 of $20 and 3 of $50 totally didnt edit it... lolol..

Ivanshal [37]2 years ago
6 0

Answer:

<u>12 $20 Bills & 3 $50 Bills</u>

Step-by-step explanation:

Because if the total is $390, Then if you get 10 $20 Bill that would equal $200 Bills and if you get 2 $50 Bills then you would get $100. Add the $200 Bills & the $100 Bills you get $300 Bills.

Then you get 1 $50 Bill and 2 $20 Dollar Bills you get $90 Bills.

Add $300 Bills with $90 Bills and you get $390.

If you add the number of bills handed it would be 15.

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Solve |x|+7&lt;4<br><br> A. 0<br> B. {x|x&lt;-11 or x&gt;-3}<br> C. {x|-3
mars1129 [50]

Answer:

{3xl42}

Step-by-step explanation:

3 0
2 years ago
If students’ scores were normally distributed and the mean was 200 with a standard deviation of 40, then what is the probability
Sonja [21]

Answer:

  84%

Step-by-step explanation:

The empirical rule tells you that 68% of the standard normal distribution is within 1 standard deviation of the mean. The distribution is symmetrical, so the amount in the lower tail is (1 -68%)/2 = 16%.

Since the number you're interested in, 240, is one standard deviation above the mean (200 +40), the percentage of interest is the sum of the area of the central part of the distribution along with the lower tail:

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4 0
2 years ago
Identify the new perimeter of the square using a scale factor of 1/3
Verizon [17]

Answer:

5

Step-by-step explanation:

15 × \frac{1}{3} = 5

5 0
2 years ago
Estimate the area of Alberta in square miles. Show your reasoning
ella [17]

Answer:  About 278,250\ mi^2

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid  can be calcualted with the formula:

A_t=\frac{h}{2}(B+b)

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

 A_r=lw

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

A=\frac{h}{2}(B+b)+lw

Substituting vallues, you get:

A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2

Therefore, the area of of Alberta is about 278,250\ mi^2.

5 0
3 years ago
Jillian measured the distance around a small fish pond as 27 yards. Which would be a good estimate for the distance across the p
ankoles [38]
27 (circumference) ➗ 3.14 (pi) = 8.59 (diameter)

Distance across (diameter) would be closest to 9.
4 0
3 years ago
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