Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Using <em>is/of=%/100 </em> 15 lawns is what % of 60
15 over 60 = % over 100
Cross multiple and divide and you should get 25%
That percent means that 25% of the lawns <em>are</em> mowed, so <u>75% </u><u></u> of the lawns need to be mowed
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0.86/5-0.3*0.5= 2 answers
1. can be 11/500
2. it can be 0.022 but im positive it has to be 11/500
Answer:
a constant
Step-by-step explanation:
Hello! There are a few things that determine whether or not something is a function. In this case, to determine whether a relation is a function, we look at the domains, which are the x-coordinates, the first number of the pair. If the number occurs in the x-coordinate for more than one pair in a relation, then it's not a function. If a number only occurs as an x-coordinate once in the relation, then it's a function. In other words, they each have only one y-coordinate in the relation. For this question, the first, second, and third relations are functions. The fourth one is not a function, because the 3 has more than one y-coordinate, so it occurs as an x-coordinate more than once. Here are the answers easier to read.
1st : yes
2nd: yes
3rd: yes
4th: no
