Aritmetic increases by the same number
geometric has 1 number that each term is multiplied by to get the next term
4 to 9 is 5
9 to 13 is 4
not same difference
9/4=13/9?
81/36=52/36?
no
neither aritmetic nor geometric
We have
Plug in
:
⇒
So we now have
Plug in
:
⇒
⇒
![b=\sqrt[3]{\frac{95}{4}}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D)
which is approximately 2.874
So we get
![y=4(\sqrt[3]{\frac{95}{4}})^{x}](https://tex.z-dn.net/?f=y%3D4%28%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D%29%5E%7Bx%7D)
or, in decimal form,
Answer:
(2n+6)^2
Step-by-step explanation:
To solve this, you can use the given formula: x^2 + 2xy + y^2
In this case, 4n^2 is x^2, 24n is 2xy, and 36 is y^2. The next step is:
(2n)^2 + 2(2n)(6) + (6)^2
Since this equation fits into this formula ( x^2 + 2xy + y^2), we can do:
(2n+6)(2n+6) =
(2n+6)^2
Hence, the answer is (2n+6)^2
7. increasing; non-linear
8.A. y=4^x
9.A. y=6x
Answer:
Y=x(squared)
Step-by-step explanation:
Use this equation to get x and y from the table
