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3 years ago

B2-4b+4=0 using quadratic forumla

Mathematics

2 answers:

Ivan3 years ago

8 0

Trying to factor by splitting the middle term

Factoring b2-4b+4
The first term is, b2 its coefficient is 1 .
The middle term is, -4b its coefficient is -4 .
The last term, "the constant", is +4 

Step-1 : Multiply the coefficient of the first term by the constant 1 • 4 = 4

Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is -4 .

-4 + -1 = -5 -2 + -2 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
 b2 - 2b - 2b - 4

Step-4 : Add up the first 2 terms, pulling out like factors :
 b • (b-2)
 Add up the last 2 terms, pulling out common factors :
 2 • (b-2)
Step-5 : Add up the four terms of step 4 :
 (b-2) • (b-2)
 Which is the desired factorization

Mashcka [7]3 years ago

3 0

Answer:

Before using the quadratic, make sure the right side is equal to 0. Check.

The quadratic formula gives the solution for an equation ,

which is .

In this case, our "a" value can be considered 1, b = -4, and c = 4.

Let's plug these values into the quadratic formula.

Another easy way to solve would be by factoring.

We would find two numbers that add to b and mutliply to equal ac.

Split our bx term into these two values

Factor and simplify.

(These numbers would be -2 and -2. Then we'd get

b² - 2b - 2b + 4. Factor the first two terms...

b(b-2) - 2b + 4. Factor the last two so that you get the same thing in the ()'s

b(b-2) -2(b-2) Combine like terms.

(b-2)(b-2) or (b-2)² is our factored form.

This is going to be equal to zero, so (b-2)² = 0.

We then look at our factors and note that any number which can cause it to equal zero is correct. Both factors are (b-2). In that case, b=2.

There's also a lot of shortcuts you could've done there such as taking the two numbers you got (say, m and n) and putting them directly into (x+n)(x+m) whenever your a value is 1.)

Step-by-step explanation:

trust me !

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Nifal earned 9$ for washing two cars .He recived $1 more for the second car.How much was he paid for washing each car?Which two

Sveta_85 [38]

Answer:

Nifal received $ 4 for washing the first car.

Nifal received $ 5 for washing the second car.

4 and 5 have a sum of 9.

Step-by-step explanation:

The problem can be rewritten as follows: Find the sum of two consecutive entire numbers equal to 9. That is:

$x + y = 9$

$y = x+1$

Then, by eliminating y:

$x + (x+1) = 9$

$2\cdot x + 1 = 9$

Now, let is clear $x$ :

$2\cdot x = 8$

$x = 4$

Nifal received $ 4 for washing the first car.

The earning for the second car is: ( $x = 4$ )

$y = x +1$

$y = 4 + 1$

$y = 5$

Nifal received $ 5 for washing the second car.

4 and 5 have a sum of 9.

8 0

3 years ago

Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ

slega [8]

Using the law of cosine for Triangle KJL, we can write:

$j^{2} = k^{2} + l^{2}-2(k)(l)cos(J) \\ \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\ \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}$

Using the values of k,j and l, we can write:

$cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)} \\ \\ 
cos(J)= 0.664 \\ \\ 
J= cos^{-1}(0.664) \\ \\ 
J=48.39$

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer

8 0

3 years ago

Read 2 more answers

Brian compared the decimals 66.10, 21.10, and 66.11.

kogti [31]

Your answer is C hope this helps

3 0

3 years ago

11 POINTS PLZ HELP EMERGENCY

Bad White [126]

Part A

The given expression is:

$(-5(1+2i)+3i(3-4i)$

We expand to get:

$-5-10i+9i-12i^2$

Note that $i^2=-1$

$12-5-10i+9i$

$-5-10i+9i+12$

$7-i$

Part Bi)

The given expression is;

$\sqrt{-50}$

We simplify to get:

$\sqrt{25\times 2\times -1}$

$\sqrt{25\times} \sqr{2}\times \sqrt{-1}$

Note that:

$\sqrt{-1}=i$

$5\sqr{2}i$

This is now of the form $a+bi$ , where $a=0,b=5\sqr{2}$ .

This explains why it is a complex number;

Part bii)

The given expression is :

$\frac{\sqrt{-50} }{\sqrt{5}}$

We simplify to get

$\sqrt{\frac{-50 }{5}}$

$\sqrt{-25}$

$\sqrt{-25}=\sqrt{25}\times \sqrt{-1}$

$\sqrt{-25}=5\times i$

$\sqrt{-25}=5i$

Part C

We want to simplify:

$i^{22}$

We rewrite in terms of $i^2$

$i^{22}=(i^2)^{11}$

$i^{22}=(-1)^{11}$

$i^{22}=-11$

5 0

3 years ago

These algebraic expressions are not equivalent. Explain

dezoksy [38]

Answer:

in the 1st row, one x^2 is positive while the other is negitive, making the total zero. also in the top row 8x+(-6x) = 2x, but in the 2nd row is says -2x, showing they are not the same. Also there is no -1/2 in the 2nd row like there is in the 1st row

Step-by-step explanation:

7 0

3 years ago