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Kitty [74]
2 years ago
11

2 Explain Does figure B appear to be a reflection of figure A for each pair of

Mathematics
1 answer:
myrzilka [38]2 years ago
3 0

In first figure there is reflection but it is not present in the second figure due to absence of bouncing back of ray of light.

In the first figure which is given the image shows the inverted image of the triangle A that is the reflection of Figure A . Reflection as per the definition is the bouncing back of light wave when it is touched to a thing or obstacle. It form a image in opposite direction.

So according to it Figure A in first pair is the reflection of figure B.

Whereas in figure B there is no reflection as the mirror image is shown and not the opposite or inverted image is there.

Mirror image is the image same as the object shown or kept. so its not the reflection of Figure A. In Pair 2 Figure A is not a reflection of Figure B.

You can find more about reflection:

brainly.com/question/16339286

#SPJ9

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It snowed 134.46 inches on Monday and 8.3 inches on Tuesday. How much did it snow on Monday and Tuesday combined?
kkurt [141]

Answer

142.76

Step-by-step explanation:

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Please help me (with explanation if possible)
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Answer:

French=60,History=120,Music=108

Step-by-step explanation:

I think this is trying to represent the degrees of a pie chart.

To find the degree of the pi chart per person you need to 72/12=6

Than to find the amount of degrees per subject multiply 6*amount of students.

Example:

6 \times amoumt \: of \: students \:taking \: music = 6 \times 18 = 108

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Let f be a differentiable function on (-0o,00) such that f(-x)= f(x) for all x in (, o). Compute the value of f'(0). Justify you
snow_lady [41]

Answer:

f'(0)=0

Step-by-step explanation:

Applying the chain rule

\frac{d}{dx} (f(-x))=-\frac{df}{dx}

Then it becomes

\frac{df}{dx} =-\frac{df}{dx}

In x=0

\frac{d[tex]f'(0)=-f'(0)\\f'(0)+f'(0)=0\\2f'(0)=0\\f}{dx} =-\frac{df}{dx}[/tex]

Then

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8 0
3 years ago
A hair salon charges a fixed rate of $25.00 for a haircut and an additional $15 for any other services. Write a function to mode
Lynna [10]

Answer:

A

Step-by-step explanation:

The function is f(x) = 15x + 25 as 25$ is a fixed rate ( it does not change and is always charged) when 15$ for any other service which can be anything, a costumer can have 0 services other than the hair cut which gives f(0). As for the question, it's asking for haircut, shampoo, highlight, and blow dry so that is 3 other services other than the fixed haircut which means f(3). substitute x=3 in the function to get 15(3) + 25 = 45+25 = 70.

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You have been saving nickels, dimes, and quarters in a jar for about a year. You decide to see how much money you've saved up. W
anyanavicka [17]

Answer:

x = number of nickels = 127

y = number of dimes = 156

z = number of quarters = 78

Step-by-step explanation:

Let

x = number of nickels

y = number of dimes

z = number of quarters

Total worth of the coins = $41.45

Total number of coins = 361

x + y + z = 361 (1)

dime = $0.1,

nickel = $0.05

quarter = $0.25

0.05x + 0.1y + 0.25z = 41.45 (2)

twice as many dimes as quarters.

y = 2z

Substitute y = 2z into (1) and (2)

x + 2z + z = 361

0.05x + 0.1(2z) + 0.25z = 41.45

x + 3z = 361

0.05x + 0.2z + 0.25z = 41.45

x + 3z = 361 (3)

0.05x + 0.45z = 41.45 (4)

Multiply (4) by 20

x + 3z = 361 (3)

x + 9z = 829 (5)

Subtract (3) from (5)

9z - 3z = 829 - 361

6z = 468

Divide both sides by 6

z = 468 / 6

= 78

z= 78

Recall,

y = 2z

= 2(78)

= 156

y = 156

Substitute the value of y and z into

x + y + z = 361

x + 156 + 78 = 361

x + 234 = 361

x = 361 - 234

= 127

x= 127

x = number of nickels = 127

y = number of dimes = 156

z = number of quarters = 78

6 0
3 years ago
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