The weight in 1980 is 
kilograms
<em><u>Solution:</u></em>
From 1980 to 1990, Lior’s weight increased by 25%
His weight is "k" kilograms in 1990
<em><u>To find: weight in 1980</u></em>
This is a percentage increase problem
Let "x" be the weight in kilograms in 1980
<em><u>The percentage increase is given by formula:</u></em>
Here,
Initial value in 1980 = x
Final value in 1990 = k
Percentage increase = 25 %
<em><u>Substituting the values in formula,</u></em>
Thus the weight in kilograms in 1980 is
Answer:
$7995.85
Step-by-step explanation:
We will use simple interest formula to solve our given problem.
, where,
A = Amount after t years,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
Therefore, Judy will will pay back on January 20: <u>$7995.85</u>.
Answer:
a) p + q + r
b) 2(a + b)
Step-by-step explanation:
The perimeter of a two-dimensional shape is the <u>distance</u> all the way around the outside.
An algebraic expression contains one or more numbers, variables, and arithmetic operations.
A variable is a symbol (usually a letter) that represents an unknown numerical value in an equation or expression.
<u>Question (a)</u>
The length of each side of the triangle is labeled p, q and r. Therefore, the perimeter is the sum of the sides:
Perimeter = p + q + r
So the algebraic expression for the perimeter of the triangle is:
p + q + r
<u>Question (b)</u>
Not all of the sides of the shape have been labeled.
However, note that the horizontal length labeled "a" is equal to the sum of "c" and the horizontal length with no label.
Similarly, note that the vertical length labeled "b" is equal to the sum of "d" and the vertical length with no label.
Therefore, the perimeter is twice the sum of a and b:
Perimeter = 2(a + b)
So the algebraic expression for the perimeter of the shape is:
2(a + b)
Answer:
12-10=2 / (6×5)=30 / 5×2=10 / 12×2=24 / 6+5-2=9
1 sunflower = $?
8 sunflowers = $18
Divide $18 by 8 = 2.25
1 sunflower is $2.25.
