Answer: 109.1 degrees
Step-by-step explanation:
To find the angle between the given vectors, we will use the formula below:
Cos(θ) = (U.V)/ |U|.|V|
Where
U = 13i - 8j
V = 2i + 9j
U.V = (2x13) + (-8×9)
U.V = 26 - 72
U.V = - 46
|U| = sqrt ( 13^2 + 8^2)
= sqrt ( 233) = 15.264
|V| = sqrt( 2^2 + 9^2)
= sqrt ( 85 ) = 9.22
Substitute all the value of the parameters into the formula
Cos ø = -46 / (15.3 × 9.2)
Cos ø = - 46 / 140.72
Cos Ø = - 32687
Find the cos inverse of the value
Ø = cos^-1( -32687)
Ø = 109.079 degrees
Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees
Angles 4 and 6 are called Alternate Exterior Angles
Step-by-step explanation:
Alternate Exterior Angles are a pair of angles on the outer side of the each of two lines but on opposite sides of the transversal.
When we take two parallel lines they will create 8 angles, such as 1,2,3,4,5,6,7 & 8.
In that angle 6 is 65 degrees.
Angles 1,2,3 & $ are in one line and remaining four angles on other line.
So Angles 4 and 6 are alternate exterior angles.
Is there any answer choices so I can choose?
Answer:
6x-24y
Step-by-step explanation:
Step 1: -30x-12y+36x-12y
Distribute-3 to 10x and 4y
Then distribute 6 to 6x and -2y
Step 2: 6x-24y
After that add up like terms
