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3 years ago

WILL GIVE BRAINLIEST! EASY! Give detailed answer

Mathematics

1 answer:

pishuonlain [190]3 years ago

5 0

Sure I will give two examples

Application of tangents

1. If we are traveling in a car around a corner and we drive over something slippery on the round ( like water , ice or oil ) , our car starts to skid

It continue in a direction tangent to the curve

Application of tangents

2. Have you ever sat on a merry- go around

If yes , then you would understand

From your experience when I tell you that the force your experience is towards the centre of merry- go around but your velocity ( the tendency of motion) is in the way toward which your body pointing

Another way saying the same thing would be to let you know that your velocity at any point is tangent while force .

At any point is normal to the circle along which you are moving

Can you draw connection between both the ways of saying the same thing?

Have this two example help you
Good luck :D

You might be interested in

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

$P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)$

Calculation the value from standard normal z table, we have,

$P(x < 5) =0.7287= 72.87\%$

b) P( port handles 3 or more million tons of cargo per week)

$P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)$

Calculating the value from the standard normal table we have,

$1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%$

c)P( port handles between 3 million and 4 million tons of cargo per week)

$P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%$

$P(3 \leq x \leq 4) = 23.7\%$

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85$

$= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85$

$=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15$

Calculation the value from standard normal z table, we have,

$P( z \leq -1.036) = 0.15$

$\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65$

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0

3 years ago

In the following figure, EM is tangent to circle A at point C.

Sphinxa [80]

Answer:

A must be true

Step-by-step explanation:

Since ABE and angle ACE are right angles the rest of the 2 angles are right angles either therefore EC = AB

6 0

3 years ago

A company makes traffic signs one of those signs can be modeled by an equilateral triangle with the perimeter of 144 inches the

barxatty [35]

Answer:

The height of the larger traffic signs is 51.96 inches

Step-by-step explanation:

Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches

Now, A company makes similar traffic signs of perimeter 1.25 of original

New perimeter will be 1.25x144=180 inches

Let triangle ABC be a larger triangle with 180inches of the perimeter.

It is given that the triangle is an equilateral triangle,

Therefore, Side AB=BC=AC

The perimeter of a triangle ABC is

AB+BC+AC=180

3AB=180

AB=60 inches

Figure show that triangle ABC and AD is the height of the triangle.

Since, the triangle ABC is an equilateral triangle,

AD is the perpendicular bisector of BC

so that,

BD=DC and Angle ADB=90

In right triangle ADB,

Angle D =90 and Angle B =60

Side BD=60/2=30 inches and AB=60 inches

Using Pythagoras theorem,

$AD^{2} +BD^{2} =AC^{2}$

$(AD)^{2} +(30)^{2} =60^{2}$

$(AD)^{2} =60^{2}-(30)^{2}$

AD=51.96 inches

Thus, The height of the larger traffic signs is 51.96 inches

4 0

3 years ago

What is the area of a cross section that is parallel to face CDHG ?

Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

$Length\times breadth\\\\=36\times 12\\\\=432\ cm^2$

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0

3 years ago

Read 2 more answers

Which of the following is a proportion? <br><br> A. 4/6 = 6/9<br><br> B. 5/6 = 10/18

worty [1.4K]

Hey there mate!

Your correct answer would be $\left[\begin{array}{ccc}\boxed{\boxed{ 4/6 = 6/9}}\end{array}\right]$ This would be because 4/6 is almost 1 as a whole, and also, 6/9 is almost 1, as a whole, so this would totally make sense for this to be a proportional.

Hope this helps you budd!

8 0

3 years ago

Read 2 more answers