Let the price = P , the years = x , depreciation rate = d<span> and original cost = W
</span>∴
![P = W * (1-d)^x](https://tex.z-dn.net/?f=P%20%3D%20W%20%2A%20%281-d%29%5Ex)
when W = 25,000 , d = %8 = 0.08 and x =7
∴
P = 13,946.165 ≈ 13,946 to the nearest dollar
The price <span>after 7 years = $13,946</span>
Answer:
identity property of zero
Step-by-step explanation:
Answer:
3.7w - 2
Step-by-step explanation:
7.4w − 5 −3.7w + 3 Combine like-terms
7.4w - 3.7w + 3 - 5
3.7w - 2
Answer:
120
Step-by-step explanation:
Just add the 20 back to 40 and times by 2
40 + 20 = 60
60 * 2 = 120
9514 1404 393
Answer:
10%
Step-by-step explanation:
We assume the "sum" being referred to in both cases is the principal amount invested. The simple interest formula tells you ...
I = Prt . . . . . . interest on P invested at annual rate r for t years
We have ...
Filling in these values, we get ...
0.3P = Pr(3)
0.1 = r . . . . . . . . divide by 3P
The interest rate is 0.1×100% = 10% per year.