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aivan3 [116]
3 years ago
11

Karl scored 14 out of 20 in a test work out his score as a percentage

Mathematics
1 answer:
erik [133]3 years ago
8 0

Answer:

70%

Step-by-step explanation:

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A second grade student is 4 feet tall. Her teacher is 5 2/3 feet tall. How many times as tall as the student is the teacher
Alchen [17]

Answer:

The teacher is 1.416667 times taller than the student

Step-by-step explanation:

(5 2/3)/4

=1.416667

4 0
3 years ago
I need help asap thanks
Sunny_sXe [5.5K]
V=hb

h= \frac V b

h = \dfrac{ x^3 - 3x^2 + 5x - 3}{x^2 -2}

Expressing that as a quotient and remainder,

h =x - 3 = \dfrac{ 7 x - 9} { x^2 - 2}

First choice.



7 0
3 years ago
2x+y=3, 5x-2y=12 how to solve this
Leviafan [203]
Start by getting one of the equations in terms of one variable, in this case lets put the first equation in terms of y

2x+y=3 ---> y=3-2x

now we plug that into the second equation

5x-2y=12 ---> 5x-2(3-2x)=12

we can then multiply and simplify

5x-2(3-2x)=12 ---> 5x-6+4x=12 ---> 9x-6=12 ---> 9x=18 ---> x=2

we can now plug x=2 into an equation to solve for y

2(2)+y=3 ---> 4+y=3 ---> y=-1
7 0
3 years ago
Read 2 more answers
Calculate the lateral area of a rectangular prism with a base with measures of 5.6 in. and 4.3 in. and a height of 10 in.
juin [17]
One formula for the lateral area is
  A = 2(LW + H(L+W))

Filling in the given numbers, you have ...
  A = 2((5.6 in)·(4.3 in) + (10 in)·(5.6 in + 4.3 in))
  = 2(24.08 in² + 99 in²)
  = 246.16 in²
7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Aleksandr [31]
We have to determine, The tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each system of equations to its graph.
The groups of equation are as follows;

The y-intercept of equation = 1
The x-intercept of equation = -1/2
And The slope of equation = 2

Then,

At x = 0, y = 1

And at y = 0, x = -1/2

And at x = 2, y = 3

The first and second equation Corresponding with the third graph.

The y-intercept of equation = 0

The x-intercept of equation = 0

The slope of equation = 3

So at x = 0, y = 0 and at x = 2, y = 6

The equation Corresponds with the first graph

The y-intercept of equation = -2

The x-intercept of equation = 2

The slope of equation = 2

So at x = 0, y = -2 and at x = 2, y = 0

The equation Corresponds with the first graph.

The y-intercept of equation = 3

The x-intercept of equation = -2

The slope of equation = 2

So at x = 0, y = 3 and at x = -5, y = 0

The equation Corresponds with the fourth graph.

The y-intercept of equation = 2

The x-intercept of equation = -1/2

The slope of equation = 4

So at x = 0 y = 2 and at y = 0 x = -1/2 and at x = 0.5 y = 4

The equation Corresponding with the second graph.
4 0
2 years ago
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