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Triss [41]
3 years ago
9

The hang time of a basketball player who jumps a verticle distance of 2 feet (0.6m) is 2/3 seconds. What will be the hang time i

f the player reaches the same height while jumping a horizontal distance of 4 feet (1.2m) ?
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0
The hang time will be the same because the amount of time spent in the air is dependent on the vertical height. The fact that the player covers horizontal distance is simply due to him also pushing forward, instead of only upwards.
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Square the binomial below:<br> (x– 4)
likoan [24]

Answer:

x^2-8x+16

Step-by-step explanation:

(x-4)^2

x^2-4x-4x+16

x^2-8x+16

3 0
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There were 442 students at Deerlake Middle School who voted on a theme for the spring carnival. Those who voted represent 76% of
never [62]

Answer:

Option C is correct.

Step-by-step explanation:

Number of students of Deerlake middle school that voted = 442

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Let x be the total number of student.

According to the Question,

\frac{76}{100}\times x=442

x=442\times\frac{100}{76}

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7 0
3 years ago
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Elis [28]
Your answer would be 36.

Hope this helped!
8 0
3 years ago
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beks73 [17]

Answer:

Width = 16 m

Length = 4 m

Step-by-step explanation:

The area of rectangular is 64m² the length of the pool is 12 m less that the width . The situation can be represented by the equation x

Area of a rectangle = Length × Width

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Hence:

64 = (W - 12) × W

64 = W² - 12W

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Factor using

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Width = 16m

Length = W - 12

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6 0
3 years ago
If anyone knows how to do this please help, its for a test and I have to finish the course by 11:59 tonight
abruzzese [7]
The correct answer would be c. hope this helps
3 0
3 years ago
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