Question

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data. An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where 1 equals smooth dash yellow1=smooth-yellow​, 2 equals smooth dash green2=smooth-green​, 3 equals wrinkled dash yellow3=wrinkled-yellow​, and 4 equals wrinkled dash green4=wrinkled-green. Do the results make​ sense?

Answer 1

The question is missing informations. The complete question is:

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the given sample data. An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed bellow are the phenotype codes where 1 = smooth-yellow, 2 = smooth-green, 3 = wrinkled-yellow and 4 = wrinkled-green. Do these results make sense?

4 3 3 1 3 4 1 1 1 4 2 3 1 1

(a) The mean phenotype code is _____

(b) The median phenotype code is _____

(c) Select the correct choice bellow and fill in any answer boxes within your choice

(A) The mode phenotype code is ___

(B) There is no mode

(d) The midrange of the phenotype code is ___

Do the measures of center make sense?

A. Only the mode makes sense since the data is nominal.

B. All the measures of center make sense since the data is numerical

C. Only the mean, median and midrange make sense since the data is nominal

D. Only the mean, median and midrange make sense since the data is numerical.

Answer: (a) mean = 2.285

(b) median = 2.5

(c) A) The mode phenotype code is 1

(d) midrange = 2.5 and A. Only the mode makes sense since the data is nominal.

Step-by-step explanation: Mean and Median are the average value of a data set, however, median is the value in the middle of the set while mean is the average value a data set must be if all the values were the same.

(a) To calculate mean:

mean = $\frac{4+3+3+1+3+4+1+1+1+4+2+3+1+1}{14}$

mean = 2.285

(b) To find median: The set has an even number of elements (14), so, in this case, to determine the middle term:

median = $\frac{7th + 8th}{2}$

median = $\frac{2+3}{2}$

median = 2.5

(c) Mode is the value which has the highest frequency. For this data set, mode = 1, since the number 1 appears 6 times.

Mode = 1

(d) Midrange is the average of the smallest and largest on the set.

midrange = $\frac{1+4}{2}$

midrange = 2.5

Nominal variable is a type of variable used to name, categorize or label attributes that are being measured. Mode is the most common used measure of central tendency and with it, it is possible to determine if the set is unimodal (one mode) or multimodal (two or more modes). In conclusion, mode makes sense because data is nominal.